2012-08-27 71 views
0

我想弄清楚代理連接如何通過TCP工作。我已經開始下載stacksoft library並在遠程服務器上安裝Squid代理。如何通過TCP連接到http代理?

現在我試圖通過c#TcpClient連接到它。

CONNECT proxyjudge.iathao.com:80 HTTP/1.1 
HOST proxyjudge.iathao.com 

它失敗,錯誤代碼400(我試過這幾個變種,它總是失敗):

HTTP/1.0 400 Bad Request 
Server: squid/3.1.10 
Mime-Version: 1.0 
Date: Mon, 27 Aug 2012 13:25:54 GMT 
Content-Type: text/html 
Content-Length: 3295 
X-Squid-Error: ERR_INVALID_REQ 0 
Vary: Accept-Language 
Content-Language: en 
X-Cache: MISS from **** 
X-Cache-Lookup: NONE ****:*** 
Connection: close 

.... 

<h1>ERROR</h1> 
<h2>The requested URL could not be retrieved</h2> 
.... 

<div id="content"> 
<p><b>Invalid Request</b> error was encountered while trying to process the request:</p> 

<blockquote id="data"> 
<pre>CONNECT proxyjudge.iathao.com:80 HTTP/1.1 
HOST proxyjudge.iathao.com 

</pre> 
</blockquote> 

<p>Some possible problems are:</p> 
<ul> 
<li><p>Missing or unknown request method.</p></li> 
<li><p>Missing URL.</p></li> 
<li><p>Missing HTTP Identifier (HTTP/1.0).</p></li> 
<li><p>Request is too large.</p></li> 
<li><p>Content-Length missing for POST or PUT requests.</p></li> 
<li><p>Illegal character in hostname; underscores are not allowed.</p></li> 
<li><p>HTTP/1.1 <q>Expect:</q> feature is being asked from an HTTP/1.0 software.</p></li> 
</ul> 

所以我

的連接是通過以下請求開已經遵循由firefox發送到wireshark的同一服務器的請求,它看起來像一個正常的請求,沒有連接命令在望:

GET http://proxyjudge.iathao.com/ HTTP/1.1 
Host: proxyjudge.iathao.com 
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:13.0) Gecko/20100101 Firefox/13.0.1 
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 
Accept-Language: en-us,en;q=0.5 
Accept-Encoding: gzip, deflate 
DNT: 1 
Proxy-Connection: keep-alive 

====================================================== 

HTTP/1.0 200 OK 
Date: Mon, 27 Aug 2012 13:34:39 GMT 
Server: Apache 
X-Powered-By: PHP/5.3.15 
Content-Type: text/html 
X-Cache: MISS from **** 
X-Cache-Lookup: MISS from ****:**** 
Connection: close 

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> 
<head> 
<title>AZ Environment variables 1.04</title> 
</head> 
<body> 
<pre> 
HTTP_USER_AGENT = Mozilla/5.0 (Windows NT 6.1; WOW64; rv:13.0) Gecko/20100101 Firefox/13.0.1 
HTTP_HOST = proxyjudge.iathao.com 
REQUEST_URI =/
HTTP_CONNECTION = keep-alive 
REMOTE_PORT = 46153 
HTTP_ACCEPT_LANGUAGE = en-us,en;q=0.5 
HTTP_ACCEPT = text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 
REMOTE_ADDR = **** 
HTTP_CACHE_CONTROL = max-age=259200 
HTTP_ACCEPT_ENCODING = gzip, deflate 
REQUEST_METHOD = GET 
REQUEST_TIME = 1346074479 
</pre> 
</body> 
</html> 

無處不在我讀CONNECT是必要的,但在這裏它會導致一個錯誤。如果不需要連接,我如何在密碼保護的代理服務器上授權連接?

任何人都可以推薦關於此主題的好文章嗎?

+0

您使用TcpClient而不是HttpWebRequest的具體原因是什麼? – SpaceghostAli

+0

要了解http的工作方式 –

+0

如何在將命令字符串傳遞給TcpClient時格式化命令字符串?你能發佈你的C#代碼嗎? – SpaceghostAli

回答

1

據我所知你應該只發出CONNECT命令到代理,並得到響應。不是HOST命令。如果確定,其他所有內容應該是針對上游服務器的合法HTTP。