SQL顯示代替網頁

Question

我已經從我的舊電腦複製了一個codeigniter網站到我的新電腦，並複製了數據庫。當我瀏覽到該網站是在我的本地主機不過，我只是得到SQL打印出來

db->where($cell_name, $id); $this->db->delete($table_name); if (!is_array($tags)) { $tmp = array(); $tmp[] = $tags; $tags = $tmp; } if (!empty($tags)) { foreach($tags as $tag) { switch(gettype($tag)) { case 'integer': $this->db->set($cell_name, $id); $this->db->set('tag_id', $tag); $this->db->insert($table_name); break; case 'string': $tag = strtolower($tag); $results = $this->db->query('SELECT id FROM tag WHERE tag = \''.$tag.'\' LIMIT 1'); if ($results->num_rows() == 1) { $tag_id = $results->first_row()->id; } else { $this->db->set('tag', $tag); $this->db->set('permalink', url_title($tag, 'dash')); $this->db->insert('tag'); $tag_id = $this->db->insert_id(); } $this->db->set($cell_name, $id); $this->db->set('tag_id', $tag_id); $this->db->insert($table_name); break; } } } } function get_active($type, $id, $return_ids = true) { $ret = array(); switch($type) { case 'media': $table_name = 'media_tag'; $cell_name = 'media_id'; break; case 'post': $table_name = 'post_tag'; $cell_name = 'post_id'; break; } if (!$id) { $results = $this->db->query('SELECT tag.id, tag.tag, tag.permalink FROM '.$table_name.', tag WHERE tag_id = tag.id GROUP BY tag.id ORDER BY tag.tag'); if ($results->num_rows() > 0) { foreach($results->result() as $data) { if ($return_ids) $ret[] = $data->id; else $ret[] = (object) array('id' => $data->id, 'tag' => $data->tag, 'permalink' => $data->permalink); } } } else { $results = $this->db->query('SELECT tag.id, tag.tag, tag.permalink FROM '.$table_name.', tag WHERE '.$cell_name.' = '.$id.' AND tag_id = tag.id ORDER BY tag.tag'); if ($results->num_rows() > 0) { foreach($results->result() as $data) { if ($return_ids) $ret[] = $data->id; else $ret[] = (object) array('id' => $data->id, 'tag' => $data->tag, 'permalink' => $data->permalink); } } } return $ret; } } 

有誰知道，如果有一個簡單的原因 - 一些設置，我需要在WAMP打開例如，我完全處於虧損狀態，文件和數據庫是我的新老電腦相同

Answer 1

原來我根本就沒有讓「短打開標籤」從WAMP PHP設置