我有一個數組如何計算動態創建的數組的長度?
dump($data);
*************************************
array(10) {
["12-male"] => string(1) "2"
["11-male"] => string(1) "2"
["10-female"] => string(1) "2"
["16-female"] => string(1) "2"
["9-male"] => string(1) "2"
["17-male"] => string(1) "4"
["14-male"] => string(1) "4"
["15-female"] => string(1) "4"
["13-female"] => string(1) "5"
["18-female"] => string(1) "6"
}
******************************************
我動態越來越像子排列出數組的上述
$rooms = array();
foreach ($data as $key => $value) {
$rooms['room'.$value][] = $key;
$rooms['room'.$value]['count'] = sizeof($rooms['room'.$value]);
}
dump($rooms);
******************************************
我得到這樣的結果
Dump => array(4) {
["room2"] => array(6) { //array size=6
[0] => string(7) "12-male"
["count"] => int(6) //count of array size=6
[1] => string(7) "11-male"
[2] => string(9) "10-female"
[3] => string(9) "16-female"
[4] => string(6) "9-male"
}
["room4"] => array(4) { //array size=4
[0] => string(7) "17-male"
["count"] => int(4) //count of array size=4
[1] => string(7) "14-male"
[2] => string(9) "15-female"
}
["room5"] => array(2) { //array size=2
[0] => string(9) "13-female"
["count"] => int(1) //count of array size=1 (the problem here)
}
["room6"] => array(2) { //array size=2
[0] => string(9) "18-female"
["count"] => int(1) //count of array size=1 (the problem here)
}
}
我的問題是,計數在第2次迭代之後正確地返回,之後計數總是顯示1,無論數組大小如何。 我試過count(),但結果是一樣的。
如果我想保持在同一個數組中的計數呢? – VostanAzatyan
@ user3269869問題的答案是否會給你預期的結果? – xdazz
是的,幫助了我很多,謝謝....但你能告訴我如何插入計數在我創建的數組? – VostanAzatyan