SQL查詢返回只有5條記錄，而不是6行

Question

我想獲取單列中存在的數據，該列使用雙散列（##）分隔。根據我下面提到的查詢，我能夠只取5條記錄而不是6條記錄。

我可以認爲我的connectby表達式存在一些問題。任何幫助是極大的讚賞。

數據

Line1## Line2## Line3 ## Line4 ## Line5 ## Line6 ## 

查詢用來獲取被分隔雙哈希##在一條記錄記錄

複製場景：

create table temp (errormessage varchar2(300)) 

insert into temp errormessage values('Line1## Line2## Line3 ## Line4 ## Line5 ## Line6 ##') 



WITH sample_data 
    AS (SELECT errormessage AS Error_Message 
      FROM TEMP) 
SELECT Regexp_substr(error_message, ',?([^#]*)', 1, LEVEL, 'i', 1) AS Error_Message 
FROM sample_data 
WHERE Length(Regexp_substr(error_message, ',?([^#]*)', 1, LEVEL, 'i', 1)) != 0 
CONNECT BY (Regexp_count(error_message, '#') + 1 >= LEVEL AND 
      PRIOR dbms_random.value IS NOT NULL) 
ORDER BY LEVEL 

錯誤信息具有要分隔的信息的列。現在，在任何數據庫中複製問題都非常容易。

Answer 1

也許你喜歡的東西后：

WITH sample_data AS (SELECT 1 stagging_id, 
          'A' status, 
          'Line1## Line2## Line3 ## Line4 ## Line5 ## Line6 ##' error_message 
        FROM dual UNION ALL 
        SELECT 2 stagging_id, 
          'B' status, 
          'Line1## Line2## Line3 ## Line4 ## Line5 ## Line6 ##Line7 ##' error_message 
        FROM dual) 
SELECT stagging_id, 
     status, 
     regexp_substr(error_message, '[^#]+', 1, LEVEL) err_msg 
FROM sample_data 
CONNECT BY PRIOR stagging_id = stagging_id 
      AND PRIOR sys_guid() IS NOT NULL 
      AND regexp_substr(error_message, '[^#]+', 1, LEVEL) IS NOT NULL; 

STAGGING_ID STATUS ERR_MSG 
----------- ------ -------------------------------------------------------------- 
      1 A  Line1 
      1 A  Line2 
      1 A  Line3 
      1 A  Line4 
      1 A  Line5 
      1 A  Line6 
      2 B  Line1 
      2 B  Line2 
      2 B  Line3 
      2 B  Line4 
      2 B  Line5 
      2 B  Line6 
      2 B  Line7 

問題與您現有的代碼是在REGEXP_SUBSTR的*，加上您計算單#，而你的分隔符是##的事實。

你能解決您的查詢，像這樣：

WITH sample_data AS (SELECT 1 stagging_id, 
          'A' status, 
          'Line1## Line2## Line3 ## Line4 ## Line5 ## Line6 ##' error_message 
        FROM dual UNION ALL 
        SELECT 2 stagging_id, 
          'B' status, 
          'Line1## Line2## Line3 ## Line4 ## Line5 ## Line6 ##Line7 ##' error_message 
        FROM dual) 
SELECT Regexp_substr(error_message, ',?([^#]+)', 1, LEVEL, 'i', 1) AS Error_Message 
FROM sample_dataCONNECT BY (Regexp_count(error_message, '##') >= LEVEL AND 
      PRIOR stagging_id = stagging_id AND 
      PRIOR dbms_random.value IS NOT NULL) 
ORDER BY stagging_id, LEVEL; 

ERROR_MESSAGE 
-------------------------------------------------------------- 
Line1 
Line2 
Line3 
Line4 
Line5 
Line6 
Line1 
Line2 
Line3 
Line4 
Line5 
Line6 
Line7 

注意我是如何在REGEXP_SUBSTR的在regexp_count改變了* s到+ S和'#'到'##'。