我運行下面的查詢:無法插入查詢結果到SQL查詢在phpMyAdmin
SELECT *
INTO consolidated
FROM (SELECT qtyAvailable
FROM Inventory
UNION ALL
SELECT revenue,
location,
qtySold
FROM sales
UNION ALL
SELECT inactive,
new,
itemNum,
category,
subCategory,
color,
FROM Masterlist) n
而得到這些錯誤
Error
SQL query: Documentation
SELECT *
INTO consolidated
FROM (SELECT qtyAvailable
FROM Inventory
UNION ALL
SELECT revenue,
location,
qtySold
FROM sales
UNION ALL
SELECT inactive,
new,
itemNum,
category,
subCategory,
color,
FROM Masterlist) n
LIMIT 0, 25
MySQL said: Documentation
#1327 - Undeclared variable: consolidated
,當我刪除新表或「變量」這個錯誤
Error
SQL query: Documentation
SELECT *
FROM (SELECT qtyAvailable
FROM Inventory
UNION ALL
SELECT revenue,
location,
qtySold
FROM sales
UNION ALL
SELECT inactive,
new,
itemNum,
category,
subCategory,
color,
FROM Masterlist) n
LIMIT 0, 25
MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM Masterlist) n
LIMIT 0, 25' at line 16
當我刪除了n,則類似的錯誤
Error
SQL query: Documentation
SELECT *
FROM (SELECT qtyAvailable
FROM Inventory
UNION ALL
SELECT revenue,
location,
qtySold
FROM sales
UNION ALL
SELECT inactive,
new,
itemNum,
category,
subCategory,
color,
FROM Masterlist)
LIMIT 0, 25
MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM Masterlist)
LIMIT 0, 25' at line 16
我對myPHP並沒有很深的經驗,但基本上我正在數據庫中的三個表上運行一個查詢,並且我想將結果插入到一個新的表中,我稱之爲合併。我創建了統一表並將列留空。我不知道從哪裏開始,預先感謝任何幫助!我想出了基於這個初始查詢post
插入其插入'和into'當你想通過選擇插入其'插入到表從...'你的語法是錯誤的選擇,你應該提供一些樣本數據和預期的結果。當你做聯合或聯合時,所有的選擇都應該有相同的列數,這在你的情況下不是那麼重要。 –
謝謝,但我得到這個錯誤 – kat
你只要引用此鏈接http://blog.sqlauthority.com/2007/08/15/sql-server-insert-data-from-one-table-to-another-table-插入選擇選擇表/ – vishuB