2011-09-30 15 views
0

我想做一個連接到本地運行的tomcat服務器的swing程序。用戶名,密碼認證,然後用戶可以在服務器目錄中上傳文件。 ie.http://本地主機:8080/uploadfiles。從用戶定義的文件路徑,和下載到本地目錄相同。如何上傳,從用戶名,密碼在鞦韆上的tomcat服務器下載文件

+1

您是否嘗試過的HttpClient教程 - HTTP: //hc.apache.org/httpcomponents-client-ga/tutorial/html? –

+1

上面的代碼得到了java.net。*包或多或少的正確。我唯一注意到了用於POST請求的urlconnection.setDoOutput()。在閱讀服務器響應之前,您應該始終檢查urlconnection.getResponseCode()。 –

+0

你需要更多的細節來解決你遇到的問題,你如何在服務器端處理它,等等。這裏有很多未知的東西。 –

回答

1

這是一個可能性: 下載:

URL url = new URL("http://localhost:8080/uploadfiles"); 
    HttpURLConnection con = (HttpURLConnection)url.openConnection(); 
    try { 
     con.addRequestProperty("Authorization", 
       "Basic " + encode64(username + ":" + password)); 
     InputStream in = con.getInputStream(); 
     try { 
      OutputStream out = new FileOutputStream(outFile); 
      try { 
       byte buf[] = new byte[4096]; 
       for (int n = in.read(buf); n > 0; n = in.read(buf)) { 
        out.write(buf, 0, n); 
       } 
      } finally { 
       out.close(); 
      } 
     } finally { 
      in.close(); 
     } 
    } finally { 
     con.disconnect(); 
    } 

上傳:

URL url = new URL("http://localhost:8080/uploadfiles"); 
    HttpURLConnection con = (HttpURLConnection)uploadUrl.openConnection(); 
    try { 
     con.setDoOutput(true); 
     con.setRequestMethod("POST"); 
     con.addRequestProperty("Authorization", 
       "Basic " + encode64(username + ":" + password)); 
     OutputStream out = con.getOutputStream(); 
     try { 
      InputStream in = new FileInputStream(inFile); 
      try { 
       byte buffer[] = new byte[4096]; 
       for (int n = in.read(buffer); n > 0; n = in.read(buffer)) { 
        out.write(buffer, 0, n); 
       } 
      } finally { 
       in.close(); 
      } 
     } finally { 
      out.close(); 
     } 
     int code = con.getResponseCode(); 
     if (code != HttpURLConnection.HTTP_OK) { 
      String msg = con.getResponseMessage(); 
      throw new IOException("HTTP Error " + code + ": " + msg); 
     } 
    } finally { 
     con.disconnect(); 
    } 

現在,在服務器端,你將需要GET和POST請求進行區分,並相應地處理它們。您將需要一個庫來處理上傳,如Apache FileUpload

哦,在客戶端,你將需要做的Base64編碼如Apache庫commons codec

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