從數據庫中選擇Mysql

Question

我是這個東西的新手，我只是在學習。我爲NHL錦標賽做了一個頁面，現在我想縮短我的php代碼，但實際上我不知道如何。

我的問題是從數據庫中進行選擇。它變得非常複雜，但也許有辦法如何縮短它？

<?php 
    if(IS_USER){ 
$team = mysql::fetch(mysql::query(1 , "SELECT * FROM league_nhl_standings WHERE league_id = '".get_seg('ceturtais')."' AND player_id = '" . get_cookie('user_id') . "'")); 
$center = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'C'")); 
$defenseman = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'D'")); 
$goalies = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'GK'")); 
$leftw = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'LW'")); 
$rightw = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'RW'")); 

Answer 1

您可以在一個查詢中合併以下查詢。

$center = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'C'")); 
$defenseman = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'D'")); 
$goalies = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'GK'")); 
$leftw = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'LW'")); 
$rightw = mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position = 'RW'")); 

喜歡這個，

$allplayers=mysql::rows(mysql::query(1,"SELECT * FROM player_list WHERE team = '$team[team_small]' AND position IN ('C', 'D', 'GK', 'LW', 'RW')")); 

現在，您可以通過迭代列position用簡單的PHP如果條件相比較，在$allplayers和環路濾波器的結果集。

這將減少您對數據庫的查詢量並回復PHP腳本以過濾/獲取適當的數據。