無法顯示在shell腳本選項參數

這是我的shell腳本 -無法顯示在shell腳本選項參數

while getopts ":m" opt; do 
    case "$opt" in 
    m) 
     echo "-m was triggered! $OPTARG was entered" >&2 
     ;; 
    j) 
     echo "-j was triggered! $4 was entered" >&2 
     ;; 
    k) 
     echo "-k was triggered! $6 was entered" >&2 
     ;; 
    \?) 
     echo "Invalid option: -$OPTARG" >&2 
     ;; 
    esac 
done 
shift $(($OPTIND - 1))

當我運行shell腳本 -

./test.sh -m hello

我得到的輸出此way-

-m was triggered! was entered

我哪裏錯了？請耐心等待，因爲我對shell腳本完全陌生。

來源

2012-12-07 AlwaysALearner

它應該m是不是：M

while getopts "m:" opt; do

來源

2012-12-07 05:03:14 Guru

我應該怎麼做才能輸出爲'./test.sh -mytest hello'？「mytest」選項似乎不適用於現有的代碼。 – AlwaysALearner

@ user1649068：check this：http://stackoverflow.com/questions/402377/using-getopts-in-bash-shell-script-to-get-long-and-short-command-line-options – Guru

無法顯示在shell腳本選項參數

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