MYSQL選擇場，場2只，其中場1或場不等於文本

Question

我有我期待合併爲1層的SQL語法如下2 SQL語法

SELECT sentFrom 
FROM tableName 
WHERE id = :varid 
AND sentFrom != :vartext 

SELECT sentTo 
FROM tableName 
WHERE id = :varid 
AND sentTo != :vartext 

我想我應該舉個例子：

MySQL表

----------------------------------- 
sentFrom   sentTo 
1     2 
1     3 
2     1 
2     3 

查詢

select sentFrom where sentFrom != 1 and select sentTo where sentTo != 1 

返回：

sentTo 2，但不sentFrom 1

sentTo 3但不sentFrom 1

sentFrom 2，但不sentTo 1

sentFrom 2和sentTo 3

Answer 1

我認爲這應該有所幫助。

SELECT a.sentFrom , b.sentTo FROM 
(SELECT id, sentFrom FROM tableName WHERE id = :varid AND sentFrom != :vartext) a 
JOIN 
(SELECT id, sentTo FROM tableName WHERE id = :varid AND sentTo != :vartext) b 
ON a.id = b.id; 

如果你認爲，ID是不常見的，在每一個查詢選擇的行然後取下連接條件ON a.id = b.id。在這種情況下，它將返回查詢1的記錄的Cartesian product到查詢2.

Answer 2

Syntex of select query is : 
Select Colname1,Colname2,.... from tablename 
     where colname=value and/or ... 
     group by cond.. 
     having cond... 
     order by colname, colname asc/desc 
====================================== 
Ex: 

    SELECT sentFrom,sentTo FROM tableName 
     WHERE id = :varid AND (sentFrom != :vartext or sentTo != :vartext)