警告：mysqli_fetch_array（）預計參數1被mysqli_result，在C指定的字符串：\ XAMPP \ htdocs中\拍賣\線路7

Question

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, string given in C:\xampp\htdocs\auction\index.php on line 7

的index.php我如何解決這個問題？ 這是我的代碼：

<?php 
    session_start(); 
    $_SESSION['logged'] = 'guest'; 
    require("functions.php"); 
    require("htmls.php"); 
    $query = "SELECT * FROM products WHERE status = 0" or die (mysql_error()); 
    while ($row = mysqli_fetch_array($query)) 
    { 
     $datenow = date("Y-m-d"); 
     $duedate = $row['duedate']; 
     $prodid = $row['productid']; 
     if($datenow >= $duedate){ 
      $query = "UPDATE products SET status = 1 WHERE productid = '$prodid'" or die (mysqli_error()); 
     } 
    } 
    $date = date("Y-m-d"); 
    headhtml(); 
?> 

Answer 1

你忘了做查詢。

$query = "SELECT * FROM products WHERE status = 0" or die (mysqli_error()); 

應該

$query = mysqli_query("SELECT * FROM products WHERE status = 0") or die (mysqli_error()); 

而且不要忘記先連接使用mysqli_connect功能的mysqli。

如果您有查詢，請使用mysqli_fetch_array來讀取實際數據。