的Informix：查詢合併

我有2個疑問：的Informix：查詢合併

select COUNT(o.id_offer) from offers o, product p where 
p.id_product = "+ productID +" and o.id_offer = "+ offerID +" and (b.type = 0 or o.type = "A")

該查詢返回一些產品的數量

select p.id_product, p.name, s.id_supplier, s.name from product p, suppliers s where p.id_supplier = s.id_supplier

這個查詢返回的所有產品數據

我希望將二者結合起來在一個查詢，如下所示：

select (select COUNT(o.id_offer) from offers o, product p where 
p.id_product = p.id_product and o.id_offer = 13345 and (b.type = 0 or o.type = "A")) count,p.id_product, p.name, s.id_supplier, s.name from product p, suppliers s where p.id_supplier = s.id_supplier

任何人都知道如何在informix中做到這一點？

來源

2014-10-03 tck

你爲什麼標籤這個'mysql'如果它是關於Informix？ – Barmar 2014-10-03 03:15:36

對不起，謝謝修復它 – tck 2014-10-03 03:24:44

這是一個常見的錯誤，出於某種原因。你能解釋你爲什麼這麼做嗎？ – Barmar 2014-10-03 03:26:14

請使用顯式連接符號，而不是FROM子句表示法中表名的逗號列表。

第一個查詢需要泛化以生成產品ID和匹配計數。

SELECT p.id_product, COUNT(o.id_offer) AS offer_count 
    FROM offers o 
    JOIN product p ON p.id_product = o.id_product -- Guessed column 
WHERE (p.type = 0 OR o.type = 'A') 
GROUP BY p.id_product

第二個查詢可以轉換爲：

SELECT p.id_product, p.name, s.id_supplier, s.name 
    FROM product p 
    JOIN suppliers s ON p.id_supplier = s.id_supplier

這兩個查詢是可以被組合的加盟，太：

SELECT x.id_product, x.product_name, x.id_supplier, x.supplier_name, y.offer_count 
    FROM (SELECT p.id_product, p.name, s.id_supplier, s.name 
      FROM product p 
      JOIN suppliers s ON p.id_supplier = s.id_supplier 
     ) AS x 
    JOIN (SELECT p.id_product, COUNT(o.id_offer) AS offer_count 
      FROM offers o 
      JOIN product p ON p.id_product = o.id_product -- Guessed column 
     WHERE (p.type = 0 OR o.type = 'A') 
     GROUP BY p.id_product 
     ) AS y 
    ON x.id_product = y.id_product

來源

2014-10-03 04:46:28

的Informix：查詢合併

回答

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