SQL兩行

Question

我有以下稱爲數據1

DateOfBooking | Short | Long | TimeOfBooking | ID 
------------------------------------------------------- 
14.06.2016 | KAL  | blabla| 13:02   | 1 
14.06.2016 | DEF  | del | 14:02   | 3 
14.06.2016 | KAL  | blabla| 17:34   | 2 
14.06.2016 | DOL  | blub | 13:02   | 1 

我想要找的人的ID都是在KAL 13:02和DOL在13:02在那裏預訂數據庫，但查找有關的信息的人只有同時預訂（同時）。

KAL和DOL總是在同一個TimeOfBooking預訂一個ID，但我無法弄清楚如何得到結果。 我試圖

SELECT DISTINCT Data1.ID 
FROM Data1 
WHERE (((Data1.Short = 'KAL') AND (Data1.Long Like 'blabla')) 
AND ((((Data1.Short = 'DOL') AND (Data1.Long Like 'blub'))) 
Group BY Data1.ID 

當然，這並沒有工作，因爲它不僅外觀成一排。有沒有辦法查看兩行並找到相應的ID？

謝謝。

Answer 1

不太清楚你問什麼，但是這將返回數據時，KOL和DOL具有相同的ID和時間戳：

select tk.*, td.* 
from (select * from data1 where Short = 'KAL') tk 
join (select * from data1 where Short = 'DOL') td 
    ON tk.id = td.id and tk.TimeOfBooking = td.TimeOfBooking 

Answer 2

一種方法是使用聚合，通過ID和預約時間 - - 然後兩個short值檢查：

select d.id 
from data1 d 
where d.short in ('KAL', 'DOL') 
group by d.id, d.timeofbooking 
having count(distinct d.short) = 2; 

如果你想完整記錄，另一種方法是使用exists，但是是一個比較複雜一點：

select d.* 
from data1 d 
where (d.short = 'KAL' and 
     exists (select 1 from data1 d2 
       where d2.id = d.id and 
        d2.timeofbooking = d.timeofbooking and 
        d2.short = 'DOL' 
      ) 
    ) or 
     (d.short = 'DOL' and 
     exists (select 1 from data1 d2 
       where d2.id = d.id and 
        d2.timeofbooking = d.timeofbooking and 
        d2.short = 'KAL' 
      ) 
    ); 

或者，甚至，利用窗口函數：

select d.* 
from (select d.*, 
      min(short) over (partition by id, timeofbooking) as minshort, 
      max(short) over (partition by id, timeofbooking) as maxshort 
     from data1 
     where short in ('KAL', 'DOL') 
    ) d 
where minshort <> maxshort;