計數的重複值的兩列在SQL Server

Question

從這個表：

Number Value 
1  a 
2  b 
3  a 
2  c 
2  b 
3  a 
2  b 

我需要Number和Value讓所有重複的行數，即5

感謝。

Answer 1

我覺得這個查詢你想要什麼：

SELECT SUM(t.cnt) 
FROM 
(
    SELECT COUNT(*) cnt 
    FROM table_name 
    GROUP BY number, value 
    HAVING COUNT(*) > 1 
)t; 

Answer 2

Select 
    count(distinct Number) as Distinct_Numbers, 
    count(distinct Value) as Distinct_Values 
from 
    Table 

這顯示了每列中有多少個不同的值。這有幫助嗎？

Answer 3

我想你的意思是唯一編號的數量 - 值對，您可以使用：

SELECT count(*) 
FROM 
(SELECT ROW_NUMBER() OVER (PARTITION BY number, value ORDER BY (select 1)) from mytable rnk) i 
where i.rnk = 1 

Answer 4

雙方提供一個行號分區列和兩列的順序。再算上行數，其中行數大於1

查詢

;with cte as(
    select [rn] = row_number() over(
     partition by [Number], [Value] 
     order by [Number], [Value] 
    ), * 
    from [your_table_name] 
) 
select count(*) from cte 
where [rn] > 1; 

Answer 5

也許這樣的事情還大嗎？

select value,number,max(cnt) as Count_distinct from (
     select *,row_number() over (partition by value,number order by number) as cnt 
    from #sample 
    )t 
    group by value,number 

輸出

+---------------------------------+ 
    | Value | Number | Count_Distinct | 
    | a | 1 |  1  | 
    | b | 2 |  3  | 
    | c | 2 |  1  | 
    | a | 3 |  2  | 
    +---------------------------------+ 

Answer 6

可能是此查詢可以幫助你

SELECT * FROM [DBO] [Sample_table1]

;隨着 DupContactRecords（數，值，DupsCount） AS （ SELECT number R，值，COUNT（）AS TOTALCOUNT FROM [Sample_table1] GROUP BY數目，值HAVING COUNT（）> 1 ） --to得到duplicats /* SELECT * FROM DupContactRecords */ SELECT SUM（DupsCount） FROM DupContactRecords