插入MySQL的查詢，如果選中的複選框/不與PHP

Question

檢查過程中試圖開發一種複選框，激活過程基於一個複選框裏我已經發生的問題的價值，我不能讓過去的MySQL查詢，我已經試圖在

<input type="checkbox" name="status" onclick="updateStatus(<? echo $data['id']; ?>,this.checked)"> 

功能 「updateStatus」 的JavaScript/AJAX代碼爲遵循

function updateStatus(id,value) { 
if (window.XMLHttpRequest) { 
    http = new XMLHttpRequest() 
} else if (window.ActiveXObject) { 
    http = new ActiveXObject("Microsoft.XMLHTTP") 
} else { 
    alert("Your browser does not support XMLHTTP!") 
} 
http.abort(); 
http.open("GET", "../functions/ajax.php?check=update_status&id=" + id + "&checked="+value, true); 
http.onreadystatechange = function() { 
    if (http.readyState == 4) { 
     alert(http.responseText); 
    } 
} 
http.send(null) 

內部函數的PHP函數的瞬間以下/ ajax.php

if(isset($check) and $check == 'update_status' and isset($_GET['id'])){ 
    $id = mysql_real_escape_string($_GET['id']); 
    $checked= mysql_real_escape_string($_GET['checked']); 
if($checked == true) { 
    echo "Checked"; 
} elseif($checked == false) { 
    echo "Not checked"; 
} else { 
    echo "Invalid response"; 
} 

使用此代碼總是返回時，「經過」任何想法，爲什麼？

Answer 1

試試這個（測試的代碼），

<input type="checkbox" name="status" onclick="updateStatus(<? echo $data['id']; ?>,this.checked)"> 

您將獲得爲真或假的第二個參數;

function updateStatus(id,checked) { 
if (window.XMLHttpRequest) { 
    http = new XMLHttpRequest() 
} else if (window.ActiveXObject) { 
    http = new ActiveXObject("Microsoft.XMLHTTP") 
} else { 
    alert("Your browser does not support XMLHTTP!") 
} 
http.abort(); 
http.open("GET", "../functions/ajax.php?check=update_status&id=" + id+"checked="+checked, true); 
http.onreadystatechange = function() { 
    if (http.readyState == 4) { 
     alert(http.responseText); 
    } 
} 
http.send(null) 

你的PHP將是：

if(isset($check) and $check == 'update_status' and isset($_GET['id']) AND isset($_GET['checked'])){ 
$id = mysql_real_escape_string($_GET['id']); 
$checked= mysql_real_escape_string($_GET['checked']); 
if($checked == true) { 
$query = mysql_query("SELECT * FROM `check_status` WHERE `user_id` = '$_SESSION[userid]' and `id` = '$id'"); 
else 
//some other query 
//Then i can insert the query based on if the checkbox checked or not.