嘿那裏我做了一個pdo註冊表系統 - 但我用了三個類代替 - 但我沒有得到它將電子郵件/密碼插入註冊表 - 它只是進入一個空白屏幕,沒有輸入。需要數據庫輸入幫助
因此,這裏有3類代碼如下:
connect.php
<?php
class Connect{
public function dbConnex(){
return new PDO("mysql:host=localhost; dbname=demodatabase", "root","password");
}
}
?>
的header.php
<?php
include_once('Connect.php');
class Header{
public $odb;
public function __construct(){
$this->odb = new Connect();
$this->odb = $this->db->dbConnex();
}
public function Register($first_name, $last_name, $email_id, $password){
if(isset($_POST['first_name'])){
$first_name = $_POST['first_name'];
$last_name = $_POST['last_name'];
$email_id = $_POST['email_id'];
$password = $_POST['password'];
$q = "INSERT INTO demoregi(first_name, last_name, email_id, password) VALUES(:first_name, :last_name, :email_id, :password);";
$query = $odb->prepare($q);
$results = $query->execute(array(
":first_name" => $first_name,
":last_name" => $last_name,
":email_id" => $email_id,
":password" => $password
));
}
}
}
?>
的index.php
<?php
include_once('Header.php');
if(isset($_POST['submit'])){
$first_name= $_POST['first_name'];
$last_name = $_POST['last_name'];
$email_id = $_POST['email_id'];
$password = $_POST['password'];
$object = new Header();
$object -> Register($first_name, $last_name,$email_id,$password);
}
?>
<html>
<head>
</head>
<body>
<form method="post" action="header.php">
<br>First Name: <input type="text" id="first_name" name="first_name"/></br>
<br>Last Name: <input type="text" id= "last_name" name="last_name"/></br>
<br>Email: <input type="text" id="email_id" name="email_id"/></br>
<br>Password: <input type="password" id= "password" name="password"/></br>
<input type="submit" name="submit" value="Register"/>
</form>
</body>
</html>
那麼我怎樣才能把它輸入數據庫?我得到沒有錯誤信息 - 只是一個空白的屏幕,註冊按鈕重定向我。
該問題的簡單解決方案。想要一些幫助!太感謝了!!!
您需要使用'$查詢= $這個 - > odb->準備($ Q);',否則你的數據庫的處理超出範圍。 – andrewsi