Django文件上傳進度

Question

我已經使用Django文件上傳進度過程獲取進度，但得到錯誤pliks.upload" does not define a "UploadProgressCachedHandler" upload handler backend。

步驟i其次是

1）創建一個文件夾上傳並添加文件上傳處理器（UploadProgressCachedHandler.py）給它。

from django.core.files.uploadhandler import FileUploadHandler 
    from django.core.cache import cache 
    class UploadProgressCachedHandler(FileUploadHandler): 
     """ 
     Tracks progress for file uploads. 
     The http post request must contain a header or query parameter, 'X-Progress-ID' 
     which should contain a unique string to identify the upload to be tracked. 

     Copied from: 
     http://djangosnippets.org/snippets/678/ 

     See views.py for upload_progress function... 
     """ 

     def __init__(self, request=None): 
      super(UploadProgressCachedHandler, self).__init__(request) 
      self.progress_id = None 
      self.cache_key = None 

     def handle_raw_input(self, input_data, META, content_length, boundary, encoding=None): 
      self.content_length = content_length 
      if 'X-Progress-ID' in self.request.GET : 
       self.progress_id = self.request.GET['X-Progress-ID'] 
      elif 'X-Progress-ID' in self.request.META: 
       self.progress_id = self.request.META['X-Progress-ID'] 
      if self.progress_id: 
       self.cache_key = "%s_%s" % (self.request.META['REMOTE_ADDR'], self.progress_id) 
       cache.set(self.cache_key, { 
        'length': self.content_length, 
        'uploaded' : 0 
       }) 

     def new_file(self, field_name, file_name, content_type, content_length, charset=None): 
      pass 

     def receive_data_chunk(self, raw_data, start): 
      if self.cache_key: 
       data = cache.get(self.cache_key) 
       data['uploaded'] += self.chunk_size 
       cache.set(self.cache_key, data) 
      return raw_data 

     def file_complete(self, file_size): 
      pass 

     def upload_complete(self): 
      if self.cache_key: 
       cache.delete(self.cache_key) 

2）UploadProgressCachedHandler添加到您的settings.py文件：

from django.conf import global_settings 
FILE_UPLOAD_HANDLERS = ('pliks.upload.UploadProgressCachedHandler',) + \ 
    global_settings.FILE_UPLOAD_HANDLERS 

3）添加代碼以view.py

from django.core.cache import cache 
    from django.http import HttpResponse, HttpResponseServerError 

    def upload_progress(request): 
     """ 
     A view to report back on upload progress. 
     Return JSON object with information about the progress of an upload. 

     Copied from: 
     http://djangosnippets.org/snippets/678/ 

     See upload.py for file upload handler. 
     """ 
     #import ipdb 
     #ipdb.set_trace() 
     progress_id = '' 
     if 'X-Progress-ID' in request.GET: 
      progress_id = request.GET['X-Progress-ID'] 
     elif 'X-Progress-ID' in request.META: 
      progress_id = request.META['X-Progress-ID'] 
     if progress_id: 
      from django.utils import simplejson 
      cache_key = "%s_%s" % (request.META['REMOTE_ADDR'], progress_id) 
      data = cache.get(cache_key) 
      return HttpResponse(simplejson.dumps(data)) 
     else: 
      return HttpResponseServerError(
       'Server Error: You must provide X-Progress-ID header or query param.') 

4）添加網址

url(r'^admin/upload_progress/$', 
    'utils.views.upload_progress', 
    name="admin-upload-progress"), 

5）在模板

{% block extra-head %} 
    <script type="text/javascript" > 
    // Generate 32 char random uuid 
    function gen_uuid() { 
     var uuid = "" 
     for (var i=0; i < 32; i++) { 
      uuid += Math.floor(Math.random() * 16).toString(16); 
     } 
     return uuid 
    } 

    // Add upload progress for multipart forms. 
    $(function() { 
     /* 
     This throws a syntax error... 
     $('form[@enctype=multipart/form-data]').submit(function(){ 
     */ 
     $('#upload').submit(function(){ 
      // Prevent multiple submits 
      if ($.data(this, 'submitted')) return false; 

      var freq = 1000; // freqency of update in ms 
      var uuid = gen_uuid(); // id for this upload so we can fetch progress info. 
      var progress_url = '/feature/admin/upload_progress/'; // ajax view serving progress info 

      // Append X-Progress-ID uuid form action 
      this.action += (this.action.indexOf('?') == -1 ? '?' : '&') + 'X-Progress-ID=' + uuid; 

      var $progress = $('<div id="upload-progress" class="upload-progress"></div>'). 
       appendTo(document.body).append('<div class="progress-container"><span class="progress-info">uploading 0%</span><div class="progress-bar"></div></div>'); 

      // progress bar position 
      $progress.css({ 
       position: ($.browser.msie && $.browser.version < 7)? 'absolute' : 'fixed', 
       left: '50%', marginLeft: 0-($progress.width()/2), bottom: '20%' 
      }).show(); 

      // Update progress bar 
      function update_progress_info() { 
       $progress.show(); 
       $.getJSON(progress_url, {'X-Progress-ID': uuid}, function(data, status){ 
        if (data) { 
         var progress = parseInt(data.uploaded)/parseInt(data.length); 
         var width = $progress.find('.progress-container').width() 
         var progress_width = width * progress; 
         $progress.find('.progress-bar').width(progress_width); 
         $progress.find('.progress-info').text('uploading ' + parseInt(progress*100) + '%'); 
        } 
        window.setTimeout(update_progress_info, freq); 
       }); 
      }; 
      window.setTimeout(update_progress_info, freq); 

      $.data(this, 'submitted', true); // mark form as submitted. 
     }); 
    }); 
    </script> 
    {% endblock %} 

    {% block content %} 
     <form id='upload' action="." enctype="multipart/form-data" method="POST"> 
      <table> 
       {{ form.as_table }} 
      </table> 
      <p><input type="submit" value="Submit"></p> 
     </form> 
    {% endblock %} 

某處我有錯....

Answer 1

您需要提供處理程序的類名，如果你的文件名爲UploadProgressCachedHandler.py你在這裏提供的模塊名稱。你將需要使用

FILE_UPLOAD_HANDLERS = ('pliks.upload.UploadProgressCachedHandler.UploadProgressCachedHandler',) + \ 
    global_settings.FILE_UPLOAD_HANDLERS 

Python的約定將調用模塊handlers.py而不是命名它包含了下課。