輸出字母等級的問題

Question

目前我已經達到了這個程序的所有目標，除了輸出我的字母分級平均值。現在它總是輸出70而不是字母等級。有沒有人看到我的問題是什麼？我目前知道它在通過lettergrade函數後將我的歌譜值重新定義爲70。

#include<iostream> 
#include<string> 
using namespace std; 




int getexams(int count) 
{ 
    cout << "Number of exams to be entered:"; 
    cin >> count; 

    if (count > 1024) 
    { 
     cout << "Please enter a number below 1024." << endl; 
     system("pause"); 
     return 0; 
    } 
    else 
     return count; 

} 

int enterexams(int name[],int count, int b) 
{ 

    int numexams = count; 
    for (int a = 0;a < numexams;a++) 
    { 
     cout << "Enter grades: "; 
     cin >> name[a]; 
     b++; 
    } 
    return b; 

} 


char letter(double average, char lettergrade) 
{ 
    int x; 
    x = average; 
    if (x >= 90) { 
     lettergrade = 'A'; 

    } 
    else if (x >= 80) { 
     lettergrade = 'B'; 

    } 
    else if (x >= 70) { 
     lettergrade = 'C'; 

    } 
    else if (x >= 60) { 
     lettergrade = 'D'; 

    } 
    else { 
     lettergrade = 'F'; 

    } 
    return lettergrade; 


} 
void output(int count,int name[], double average, int lettergrade) 
{ 
    cout << "Number of exams: " << count << endl; 
    for (int a = 0;a < count;a++) 
     cout << "Exam grades: " << name[a] << endl; 
    cout << "Average grade: " << average << endl; 
    cout << "Letter grade: " << lettergrade << endl; 
} 
int averagecalc(int average,int count,int name[]) 
{ 
    int a,sum,x; 
    sum = 0; 

    for (a = 0;a < count;a++) 
    { 
     sum += name[a]; 

    } 
    average = sum/count; 
    return average; 
} 
int main() 
{ 
    char lettergrade = 0; 
    int b = 0; 
    int total = 0; 
    double average = 0; 
    int count =0; 
    count = getexams(count); 
    // Number of exams 

    int exams = count; 
    const int x = exams;   // Exam Values 
    int name[1024]; 

    enterexams(name,count,b); 
    average = averagecalc(average,count,name); 
    lettergrade = letter(average, lettergrade); 
    output(count, name, average, lettergrade); 

    system("pause"); 
    return 0; 
} 

Answer 1

的output函數的定義是這樣的：

void output(/*stuff*/ int lettergrade) 

這裏lettergrade是整數，但你希望它是一個char，所以你應該更改相應的定義。