我想交錯執行兩個獨立的線程。因此兩者都有10次迭代的運行方法,並且在每次迭代之後,我想要上下文切換線程。java線程交錯
線程A開始並在完成像打印之類的事情之後,將控制權交給線程B.然後線程B打印並將控制權交還給A等,直到兩者都完成爲止。
這樣做的有效機制是什麼?
我附上一個示例代碼。希望你能幫助。
// Suspending and resuming a thread for Java 2
class NewThread implements Runnable {
String name; // name of thread
Thread t;
// boolean suspendFlag;
NewThread(String threadname) {
name = threadname;
t = new Thread(this, name);
System.out.println("New thread: " + t);
// suspendFlag = false;
t.start(); // Start the thread
}
public String getState()
{
Thread t=Thread.currentThread();
return t.getState().toString();
}
// This is the entry point for thread.
public void run() {
try {
for(int i = 15; i > 0; i--) {
System.out.println(name + ": " + i);
Thread.sleep(200);
synchronized(this) {
//SuspendResume.suspendFlag2=false;
SuspendResume.suspendFlag1=true;
while(SuspendResume.suspendFlag1) {
wait();
//System.out.println(SuspendResume.ob1.t.getState().toString());
// if(SuspendResume.ob2.t.getState().toString()=="WAITING")
// SuspendResume.ob2.t.notify();
}
}
}
} catch (InterruptedException e) {
System.out.println(name + " interrupted.");
}
System.out.println(name + " exiting.");
}
void mysuspend() {
// suspendFlag = true;
}
synchronized void myresume() {
// suspendFlag = false;
notify();
}
}
class NewThread2 implements Runnable {
String name; // name of thread
Thread t;
// boolean suspendFlag;
NewThread2(String threadname) {
name = threadname;
t = new Thread(this, name);
System.out.println("New thread: " + t);
// suspendFlag = false;
t.start(); // Start the thread
}
public String getState()
{
Thread t=Thread.currentThread();
return t.getState().toString();
}
// This is the entry point for thread.
public void run() {
try {
for(int i = 15; i > 0; i--) {
System.out.println(name + ": " + i);
Thread.sleep(1000);
synchronized(this) {
//SuspendResume.suspendFlag1=false;
//while(SuspendResume.suspendFlag1) {
// while(suspendFlag) {
//wait();
//System.out.println(SuspendResume.ob2.t.getState().toString());
//if(SuspendResume.ob1.t.getState().toString()=="WAITING")
//SuspendResume.ob1.t.notify();
//}
SuspendResume.suspendFlag1=false;
notify();
}
}
} catch (InterruptedException e) {
System.out.println(name + " interrupted.");
}
System.out.println(name + " exiting.");
}
void mysuspend() {
// suspendFlag = true;
}
synchronized void myresume() {
// suspendFlag = false;
notify();
}
}
class SuspendResume {
static boolean suspendFlag1=false;
static NewThread ob1 = new NewThread("One");
static NewThread2 ob2 = new NewThread2("Two");
// static boolean suspendFlag2=false;
public static void main(String args[]) {
try {
//Thread.sleep(1000);
//ob1.mysuspend();
//System.out.println("Suspending thread One");
//Thread.sleep(1000);
//ob1.myresume();
//System.out.println("Resuming thread One");
// ob2.mysuspend();
//System.out.println("Suspending thread Two");
Thread.sleep(1000);
// ob2.myresume();
//System.out.println("Resuming thread Two");
} catch (InterruptedException e) {
System.out.println("Main thread Interrupted");
}
// wait for threads to finish
try {
System.out.println("Waiting for threads to finish.");
System.out.println(ob1.getState());
System.out.println(ob1.getState());
ob1.t.join();
ob2.t.join();
} catch (InterruptedException e) {
System.out.println("Main thread Interrupted");
}
System.out.println("Main thread exiting.");
}
}
首先,您可能在發佈之前清理了您的代碼。您可以使用'Thread.yield()'方法。它放棄CPU。但它不掛起調用線程,它處於就緒隊列中。 – 2013-03-11 12:48:25
你爲什麼要這樣做?大多數情況下,線程完成一個工作單元然後退出。控制線程可以啓動線程並等待它們完成。 – 2013-03-11 12:49:01
@GilbertLeBlanc大多數情況下,線程被寫爲while循環,直到應用關閉時纔會終止。 – 2013-03-11 12:54:16