SQL服務器和在單個查詢

Question

這裏是細節

TBL1

rec_id, rec_amount,  rec_date 

1   1500    1/1/2011 
2   4500    1/1/2011 
3   500    1/1/2011 
4   15000    1/1/2011 
5   7500    1/1/2011 

tbl2的

vouc_id  vouc_amount  pay_date 
1    15000    1/1/2011 
2    750.50   1/1/2011 
3    560    1/1/2011 

TBL3

don_id  d_amount   d_date 
1   1500    1/1/2011 
2    2000    1/1/2011 

我需要sum(rec_amount) from tbl1和sum(vouc_amount) from tbl2和sum(d_amount) from tbl3在單個查詢中where date = 1/1/2011。任何機構都可以幫助我嗎？

Answer 1

使用UNION ALL表之間做對

例如頂部

SELECT SUM(TheAmount) 
FROM(
SELECT rec_amount AS TheAmount 
FROM tbl1 
WHERE rec_date = '20110101' 
UNION ALL 
SELECT vouc_amount   
FROM tbl2 
WHERE pay_date = '20110101' 
UNION ALL 
SELECT d_amount   
FROM tbl3 
WHERE d_date = '20110101') x 

或彼此相鄰

SELECT SUM(rec_amount) AS tbl1Amount,(SELECT SUM(vouc_amount) 
FROM tbl2 
WHERE pay_date = '20110101') AS tbl2Amount ,(SELECT SUM(d_amount)   
FROM tbl3 
WHERE d_date = '20110101') AS tbl3Amount 
FROM tbl1 
WHERE rec_date = '20110101' 

Answer 2

你可以做一個子選擇每個SUM柱。

declare @T1 table(rec_id int, rec_amount int, rec_date datetime) 
declare @T2 table(vouc_id int, vouc_amount int, pay_date datetime) 
declare @T3 table(don_id int, d_amount int, d_date datetime) 

insert into @T1 values 
(1, 1500 , '2011-01-01'), 
(2, 4500 , '2011-01-01'), 
(3, 500 , '2011-01-01'), 
(4, 15000, '2011-01-01'), 
(5, 7500 , '2011-01-01') 


insert into @T2 values 
(1, 15000, '2011-01-01'), 
(2, 750 , '2011-01-01'), 
(3, 560 , '2011-01-01') 

insert into @T3 values 
(1, 1500, '2011-01-01'), 
(2, 2000, '2011-01-01') 


select 
(select sum(rec_amount) 
from @T1 
where rec_date = '2011-01-01'), 
(select sum(vouc_amount) 
from @T2 
where pay_date = '2011-01-01'), 
(select sum(d_amount) 
from @T3 
where d_date = '2011-01-01')