找到HTTP請求與URI [/ FitnessTracker /]沒有映射

Question

我正在一個WARNNING在用SpringMVC 如否的DispatcherServlet找到HTTP請求與URI [/ FitnessTracker /]名爲 'fitTrackerServlet'

INFO: FrameworkServlet 'fitTrackerServlet': initialization completed in 2194 ms 
Feb 26, 2017 9:43:08 AM org.springframework.web.servlet.DispatcherServlet noHandlerFound 
WARNING: No mapping found for HTTP request with URI [/FitnessTracker/] in DispatcherServlet with name 'fitTrackerServlet' 

映射

當我按下url http://localhost:8080/fitnessTracker/我得到404錯誤。 感謝

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> 
    <servlet> 
    <servlet-name>fitTrackerServlet</servlet-name> 
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
    <init-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>/WEB-INF/config/servlet-config.xml</param-value> 
    </init-param> 
    </servlet> 
<servlet-mapping> 
    <servlet-name>fitTrackerServlet</servlet-name> 
    <url-pattern>/*</url-pattern> 
</servlet-mapping> 
    <display-name>Archetype Created Web Application</display-name> 
</web-app> 

和我的servlet-config.xml中

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:context="http://www.springframework.org/schema/context" 
    xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xmlns:p="http://www.springframework.org/schema/p" 
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.2.xsd 
     http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd 
     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd"> 

    <mvc:annotation-driven /> 
    <context:component-scan base-package="com.pluralsight.controller"></context:component-scan> 

    <!-- 
    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
    <property name="prefix" value="/WEB-INF/jsp/"/> 
    <property name="suffix" value=".jsp"/> 
    </bean> 
    --> 

    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" 
    p:prefix="/WEB-INF/jsp/" p:suffix=".jsp"/> 

</beans> 

和我的控制器

@Controller 
public class HelloController { 

    @RequestMapping(value = "/greeting") 
    public String sayHello (Model model) { 
     System.out.println("Test"); 

     model.addAttribute("greeting", "Hello WorldX"); 
     return "hello"; 
    } 
} 

Answer 1

貴組件掃描基礎包的包在您HelloController是匹配嗎？如果不是，那就是問題所在。

<context:component-scan base-package="com.pluralsight.controller"></context:component-scan> 

配置組件掃描指令用於與@Configuration 類使用。可以指定basePackageClasses（）或 basePackages（）（或其別名值（））來定義 要掃描的特定軟件包。

Spring沒有找到你的HelloController，所以沒有映射任何東西。

否則，您也可以按照these的步驟操作。

Answer 2

我想知道爲什麼你有你的應用程序配置XML。使用this工具，您可以使用Spring啓動應用程序啓動Maven項目，默認情況下，該項目已經配置爲完全按照您的需要進行構建。

然後你只需要使用一個類：

@RestController 
@RequestMapping("/fitnessTracker") 
public class HelloController { 

    @RequestMapping(value = "/greeting") 
    public String sayHello (Model model) { 
     System.out.println("Test"); 

     model.addAttribute("greeting", "Hello WorldX"); 
     return "hello"; 
    } 
} 

就是這樣，Spring會爲你做的休息;）