沒有映射我得到這個誤差找到HTTP請求與URI
沒有映射在DispatcherServlet的發現HTTP請求與URI [/ VAL/valsys/AUTH /登錄]名爲 'VAL'
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>val</display-name>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-security.xml
/WEB-INF/applicationContext.xml
/WEB-INF/dwr-context.xml
</param-value>
</context-param>
<context-param>
<param-name>log4jConfigLocation</param-name>
<param-value>/WEB-INF/classes/log4j.properties</param-value>
</context-param>
<context-param>
<param-name>log4jRefreshInterval</param-name>
<param-value>1000</param-value>
</context-param>
<servlet>
<servlet-name>val</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>val</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>val</servlet-name>
<url-pattern>/valsys/dwr/*</url-pattern>
</servlet-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.security.web.session.HttpSessionEventPublisher</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
這是怎麼我的dispatcher.xml樣子..
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">
<!-- Declare a view resolver -->
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/" p:suffix=".jsp" />
</beans>
感謝幫助 – bala
我有一個@Controller在我的項目 @Controller @RequestMapping( 「/ AUTH」) 公共類LoginLogoutController {\t \t @資源(名稱= 「的SessionRegistry」) \t普里瓦e SessionRegistryImpl sessionRegistry; \t \t @RequestMapping(值= 「/登錄」,方法= RequestMethod.GET) \t公共字符串getLoginPage() \t \t { \t \t的System.out.println( 「在登錄頁面控制器」); \t \t return「login」; \t} 和 INFO efaultAnnotationHandlerMapping - 映射的URL路徑[/認證/註冊]到處理程序[[email protected]] 在我的控制檯....請回復 – bala