4
我試圖從評語表和issue_assigneduser表中的相關記錄計數一起檢索問題表中的字段。如果有2篇評論和6級分配的用戶,我回來的值是12,這兩個方面。任何想法如何彌補這一點?SQL - 與LEFT OUTER JOIN計數是不正確
SELECT issue.issueid, COUNT(comment.commentid) AS CountOfComments,
Count(issue_assigneduser.userid) as CountOfAssignedUsers,
issue.title, issue.detail, issue.enteredby,
issue.datetimeentered, issue.assignedto, issue.categoryid,
issue.severityid, issue.statusid,
issue.lastcommentdatetime as LastCommentDateTime,
issue.lastcommentbyuserid,
users.initials as LastCommentUserInitials,
lookupstatus.status as Status,
lookupcategory.category as Category,
lookupseverity.severity as Severity,
GetUTCDate() as UTCDateTime
FROM issue
INNER JOIN lookupcategory ON issue.categoryid = lookupcategory.categoryid
INNER JOIN lookupseverity ON issue.severityid = lookupseverity.severityid
INNER JOIN lookupstatus ON issue.statusid = lookupstatus.statusid
LEFT OUTER JOIN comment ON issue.issueid = comment.issueid
LEFT OUTER JOIN issue_assigneduser ON issue.issueid = issue_assigneduser.issueid
LEFT OUTER JOIN users ON issue.lastcommentbyuserid = users.userid
GROUP BY issue.issueid, issue.title, issue.detail,
issue.enteredby, issue.datetimeentered,
issue.assignedto, issue.categoryid,
issue.severityid, issue.statusid,
issue.lastcommentdatetime,
issue.lastcommentbyuserid,
users.initials, lookupstatus.status,
lookupcategory.category,
lookupseverity.severityid, users.initials,
lookupstatus.status, lookupcategory.category,
lookupseverity.severity
ORDER BY issue.lastcommentdatetime DESC;
只是看出來,如果同一個用戶分配兩次,他將只一次用這種方法計算。 – pocketfullofcheese
感謝您的警告。我的表格被設計爲使同一個用戶不能被分配兩次。 – HK1