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我曾嘗試下面的代碼來運行JSON與GSON相同嗎?
Gson gson = new Gson();
String json = gson.toJson(result);
JSONObject jsonResponse = new JSONObject();
jsonResponse.put("sEcho", echo);
jsonResponse.put("iTotalRecords", iTotalRecords);
jsonResponse.put("iTotalDisplayRecords", iFilteredTotalRecords);
jsonResponse.put("aaData", json);
jsonResponse.toString();
JSONArray data = new JSONArray();
for (Object obj : result) {
JSONArray row = new JSONArray();
User user = (User) obj;
row.put(user.getId()).put(user.getUserName()).put(user.isEnabled());
data.put(row);
}
JSONObject jsonResponse2 = new JSONObject();
jsonResponse2.put("sEcho", echo);
jsonResponse2.put("iTotalRecords", iTotalRecords);
jsonResponse2.put("iTotalDisplayRecords", iFilteredTotalRecords);
jsonResponse2.put("aaData", data);
jsonResponse2.toString();
從兩個jsonResponse ToString函數的結果如下:
{"iTotalDisplayRecords":11,"iTotalRecords":11,"aaData":"[{\"creationTime\":0,\"enabled\":true,\"id\":1,\"loginDuration\":0,\"online\":false,\"password\":\"asda\",\"userName\":\"abiieez\"}]","sEcho":"1"}
{"iTotalDisplayRecords":11,"iTotalRecords":11,"aaData":[[1,"abiieez",true]],"sEcho":"1"}
我想之前[和後]從以消除「符號第一個JSON響應就像第二個(我注意到「在將數組放入jsonResponse對象後添加」)。我怎樣才能做到這一點?