SQL將表連接到其他表兩次

我有這個sql用於通過連接3個表，sample_register，villages和water_cssr來獲取數據。SQL將表連接到其他表兩次

SELECT 
    sample_register.location, 
    sample_register.description, 
    villages.distance, 
    case when water_cssr.istp='Cs' then COUNT(water_cssr.usin) end as total_cs, 
    case when water_cssr.bdl='Y'and water_cssr.istp='Cs' then COUNT(water_cssr.usin) end as bdl_cs, 
    case when water_cssr.bdl='N'and water_cssr.istp='Cs' then min(water_cssr.activity) end as csmin, 
    case when water_cssr.bdl='N'and water_cssr.istp='Cs' then max(water_cssr.activity) end as csmax, 
    case when water_cssr.istp='Sr' then COUNT(water_cssr.usin) end as total_sr, 
    case when water_cssr.bdl='Y'and water_cssr.istp='Sr' then COUNT(water_cssr.usin) end as bdl_sr, 
    case when water_cssr.bdl='N' and water_cssr.istp='Sr' then min(water_cssr.activity) end as srmin, 
    case when water_cssr.bdl='N' and water_cssr.istp='Sr' then max(water_cssr.activity) end as srmax 
FROM sample_register 
LEFT JOIN villages on sample_register.location=villages.location 
LEFT JOIN sample_allocation on sample_register.usin=sample_allocation.usin 
INNER JOIN water_cssr ON water_cssr.usin = sample_register.usin 
GROUP BY sample_register.location, sample_register.description, sample_allocation.cs 
order by villages.dist_group, villages.location

我得到這樣

 
Location Type Distance Total_cs Bdl_cs Csmin csmax Total_sr Bdl_sr Srmin srmax 
A   TYPE1 5            1   1 
B   TYPE2 10   1   1  4  12 
B   TYPE2 10            1   1  1  8 
C   TYPE3 15            1   1  9  14 
C   TYPE3 15   1   1  15  24 
D   TYPE1 10            1   1 
E   TYPE2 10   1   1 
F   TYPE1 20   1   1

在上述地點B中的結果和C有兩排，每排有一排具有價值在4至7列和另一排在第八值第11列。我想將這兩行的內容放在一行中，因爲第一列到第三列的值對於兩行都是通用的。例如連續兩個和三個組合應該產生一排這樣的

 
B TYPE2 10 1 1 4 12 1 1 1 8

請幫我重組SQL

來源

2014-04-08 mansoondreamz

爲什麼您sample_register.location，sample_register.description，sample_allocation.cs分組的全部三場小組嗎？哪一列導致第2行和第3行不被聚合？ – RobP

sample_allocation.cs阻止聚合 – mansoondreamz

@Serpiton你說得對。但我的要求是獲取位置和描述的聚合，並在相應的列中顯示sr和cs的值。目前cs和sr的值在water_cssr表的同一列中，而另一列指定的值是cs或sr – mansoondreamz

我做了兩個子查詢，並加入像這樣

SELECT * FROM (SELECT 
sample_register.location, 
sample_register.description, 
villages.distance, villages.direction, 
case when water_cssr.istp='Cs' then COUNT(water_cssr.usin) end as total_cs, 
case when water_cssr.bdl='Y'and water_cssr.istp='Cs' then COUNT(water_cssr.usin) end as bdl_cs, 
case when water_cssr.bdl='N'and water_cssr.istp='Cs' then min(water_cssr.activity) end as csmin, 
case when water_cssr.bdl='N'and water_cssr.istp='Cs' then max(water_cssr.activity) end as csmax 
FROM 
sample_register LEFT JOIN villages on sample_register.location=villages.location LEFT JOIN sample_allocation on sample_register.usin=sample_allocation.usin INNER JOIN water_cssr ON water_cssr.usin = sample_register.usin 
WHERE mid(sample_register.usin,3,1)='N' and sample_register.doc between '$start_date' and '$end_date' AND water_cssr.istp='Cs' GROUP BY sample_register.location, sample_register.description, sample_allocation.cs order by villages.dist_group, villages.location) AS a left JOIN (SELECT 
sample_register.location, 
sample_register.description, 
villages.distance, villages.direction, 
case when water_cssr.istp='Sr' then COUNT(water_cssr.usin) end as total_sr, 
case when water_cssr.bdl='Y'and water_cssr.istp='Sr' then COUNT(water_cssr.usin) end as bdl_sr, 
case when water_cssr.bdl='N'and water_cssr.istp='Sr' then min(water_cssr.activity) end as srmin, 
case when water_cssr.bdl='N'and water_cssr.istp='Sr' then max(water_cssr.activity) end as srmax 
FROM 
sample_register LEFT JOIN villages on sample_register.location=villages.location LEFT JOIN sample_allocation on sample_register.usin=sample_allocation.usin INNER JOIN water_cssr ON water_cssr.usin = sample_register.usin 
WHERE mid(sample_register.usin,3,1)='N' and sample_register.doc between '$start_date' and '$end_date' AND water_cssr.istp='Sr' GROUP BY sample_register.location, sample_register.description, sample_allocation.cs order by villages.dist_group, villages.location) as b on a.location=b.location and a.description=b.description"

來源

2014-04-26 06:36:15 mansoondreamz

這只是一個概念：

查找哪些表或表加入該回報B和C爲2行。
爲該表或表加入創建查詢，因此它將爲b和c以及其他記錄返回1行。
然後修改您的查詢以在連接中使用新查詢，如果正確b 和c不會返回2行。

好運

來源

2014-04-08 08:16:36 cyan

SQL將表連接到其他表兩次

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