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我有5個表的數據庫。每個表是前一個的subcatagory，叫做：用sql ajax級聯下拉菜單
- 國家
- 狀態
- 城市
- 郵編
- 街道
現在我有3個下拉菜單這取決於每個其他。所以當我選擇countries: USA時，下一個下拉列表只會顯示美國各州等。這是有效的。
但是現在我想擴展到5個下拉列表，所以再加上2個下拉列表。
我沒有顯示我試圖添加2個以上，因爲它可能只會使它更復雜。
所以我展示3個下拉菜單，現在正在努力：
文件：ajax.php
<?php
//dbConfig is not added here, but it connects to database
include('dbConfig.php');
if(isset($_POST["country_id"]) && !empty($_POST["country_id"])){
//Get all state data
$query = $db->query("SELECT * FROM states WHERE country_id = ".$_POST['country_id']." AND status = 1 ORDER BY state_name ASC");
//Count total number of rows
$rowCount = $query->num_rows;
//Display states list
if($rowCount > 0){
echo '<option value="">Select state</option>';
while($row = $query->fetch_assoc()){
echo '<option value="'.$row['state_id'].'">'.$row['state_name'].'</option>';
}
}else{
echo '<option value="">State not available</option>';
}
}
if(isset($_POST["state_id"]) && !empty($_POST["state_id"])){
//Get all city data
$query = $db->query("SELECT * FROM cities WHERE state_id = ".$_POST['state_id']." AND status = 1 ORDER BY city_name ASC");
//Count total number of rows
$rowCount = $query->num_rows;
//Display cities list
if($rowCount > 0){
echo '<option value="">Select city</option>';
while($row = $query->fetch_assoc()){
echo '<option value="'.$row['city_id'].'">'.$row['city_name'].'</option>';
}
}else{
echo '<option value="">City not available</option>';
}
}
?>
****The index.php-file**** (I didn't add the css):
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<script src="jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#country').on('change',function(){
var countryID = $(this).val();
if(countryID){
$.ajax({
type:'POST',
url:'ajaxData.php',
data:'country_id='+countryID,
success:function(html){
$('#state').html(html);
$('#city').html('<option value="">Select state first</option>');
}
});
}else{
$('#state').html('<option value="">Select country first</option>');
$('#city').html('<option value="">Select state first</option>');
}
});
$('#state').on('change',function(){
var stateID = $(this).val();
if(stateID){
$.ajax({
type:'POST',
url:'ajaxData.php',
data:'state_id='+stateID,
success:function(html){
$('#city').html(html);
}
});
}else{
$('#city').html('<option value="">Select state first</option>');
}
});
});
</script>
</head>
<body>
<div class="select-boxes">
<?php
//Include database configuration file
include('dbConfig.php');
//Get all country data
$query = $db->query("SELECT * FROM countries WHERE status = 1 ORDER BY country_name ASC");
//Count total number of rows
$rowCount = $query->num_rows;
?>
<select name="country" id="country">
<option value="">Select Country</option>
<?php
if($rowCount > 0){
while($row = $query->fetch_assoc()){
echo '<option value="'.$row['country_id'].'">'.$row['country_name'].'</option>';
}
}else{
echo '<option value="">Country not available</option>';
}
?>
</select>
<select name="state" id="state">
<option value="">Select country first</option>
</select>
<select name="city" id="city">
<option value="">Select state first</option>
</select>
</div>
</body>
</html>
所以有什麼問題？ –
我需要2個更多的下拉菜單的表'郵編'和'街道'。郵政編碼是「城市」的一個子類別。街道是'郵編'的子類別。 –