5
結果,我有以下查詢:更新多行基於從子查詢
SELECT
stat.mcq_id,
ROUND(stat.total_score/stat.num_taken, 2) AS avg_score
FROM (
SELECT
user_mcq.mcq_id,
SUM(score) AS total_score,
COUNT(user_mcq.id) AS num_taken
FROM user_mcq
INNER JOIN user ON (user.id = user_mcq.user_id)
WHERE user.level_id =3
AND user_mcq.is_complete =1
GROUP BY user_mcq.mcq_id
) AS stat
這將產生:
mcq_id avg_score
1 5.75
2 9.22
6 8.81
7 8.94
14 7.00
16 9.46
我想用它來更新另一個表使用名爲mcq
mcq_id
從結果來匹配mcq.id
我試過以下,但沒有成功:
UPDATE mcq SET mcq.avg_score = stats.avg_score FROM (
SELECT
stat.mcq_id,
ROUND(stat.total_score/stat.num_taken, 2) AS avg_score
FROM (
SELECT
user_mcq.mcq_id,
SUM(score) AS total_score,
COUNT(user_mcq.id) AS num_taken
FROM user_mcq
INNER JOIN user ON (user.id = user_mcq.user_id)
WHERE user.level_id =3
AND user_mcq.is_complete =1
GROUP BY user_mcq.mcq_id
) AS stat
) AS stats
WHERE mcq.id = stats.mcq_id;
這給:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM (SELECT stat.mcq_id, ROUND(stat.total_score/stat.num_taken, 2) A' at line 1
完美,非常感謝! :) – Adam
不錯..這真是節省我的時間.. – faruk