集團和總和

我無法獲得業務代碼相同的註冊總和。我的代碼如下：集團和總和

SELECT DISTINCT lb.building_code , lb.bus_code, gl.building_name, gl.bus_name, SUM(gl.enrollment) AS enrollment 
    FROM table1 AS gl 
    RIGHT OUTER JOIN table 2 AS lb ON gl.building_key = lb.building_key 
    where gl.bus_name = 'Business' 
    and gl.year_cd = 2010 
    GROUP BY lb.building_code, lb.bus_code, gl.building_name, gl.bus_name, gl.enrollment

電流輸出：

building_code bus_code bus_name  enrollment 
4581    0000  Business A 12 
4581    0000  Business A 13 
4581    0109  Business B 100 
4581    0109  Business B 120 
4581    0209  Business C 130 
4581    0402  Business D 35

所需的輸出：

building_code bus_code bus_name  enrollment 
    4581    0000  Business A 25 
    4581    0109  Business B 220 
    4581    0209  Business C 130 
    4581    0402  Business D 35

來源

2013-04-05 Tone

對不起SQL服務器 – Tone 2013-04-05 17:09:54

嘗試刪除入學率從您的集團聲明。 – zundarz 2013-04-05 17:13:34

爲什麼你有'DISTINCT' *和*'GROUP BY'？當你在WHERE子句中過濾外部表時，爲什麼一個'RIGHT JOIN'，無論如何都使它成爲'INNER JOIN'？ – 2013-04-05 17:38:30

從GROUP BY條款刪除gl.building_name, gl.enrollment：

SELECT 
    lb.building_code , 
    lb.bus_code, 
    gl.bus_name, 
    SUM(gl.enrollment) AS enrollment 
FROM table1 AS gl 
RIGHT OUTER JOIN table 2 AS lb ON gl.building_key = lb.building_key 
where gl.bus_name = 'Business' 
    and gl.year_cd = 2010 
GROUP BY lb.building_code, lb.bus_code, gl.bus_name;

來源

2013-04-05 17:11:34

SELECT lb.building_code, 
     lb.bus_code, 
     gl.bus_name,  
     SUM(gl.enrollment) AS enrollment 
    FROM table1 AS gl 
    RIGHT OUTER JOIN table 2 AS lb ON gl.building_key = lb.building_key 
    where gl.bus_name = 'Business' 
    and gl.year_cd = 2010 
    GROUP BY lb.building_code, 
      lb.bus_code, 
      gl.bus_name

來源

2013-04-05 17:10:15

我會考慮兩次重寫。一，如果你的意思是這是一個外連接（所以包括table2中不在table1中的行），改變順序，使其成爲左連接，將table1的where子句移入join子句，刪除distinct，並從組中刪除非分組列：

SELECT lb.building_code, lb.bus_code, gl.building_name, 
    gl.bus_name, SUM(gl.enrollment) AS enrollment 
FROM dbo.table2 AS lb 
LEFT OUTER JOIN dbo.table1 AS gl 
    ON gl.building_key = lb.building_key 
    AND gl.bus_name = 'Business' 
    AND gl.year_cd = 2010 
GROUP BY lb.building_code, lb.bus_code, gl.building_name, gl.bus_name;

（對於絕大多數的人來說，LEFT JOIN比RIGHT JOIN直觀得多。）

如果你真的不希望從table2中有任何不在table1中的行，則不要將其寫爲外連接：

SELECT lb.building_code, lb.bus_code, gl.building_name, 
    gl.bus_name, SUM(gl.enrollment) AS enrollment 
FROM dbo.table2 AS lb 
INNER JOIN dbo.table1 AS gl 
    ON gl.building_key = lb.building_key 
WHERE gl.bus_name = 'Business' 
    AND gl.year_cd = 2010 
GROUP BY lb.building_code, lb.bus_code, gl.building_name, gl.bus_name;

來源

2013-04-05 17:42:23

嘗試

由於您使用右外連接，所以不要忘記添加ISNULL在SUM聚合函數來處理從表中的數據不匹配2

SELECT lb.building_code , lb.bus_code, gl.bus_name, SUM(Isnull(gl.enrollment,0)) AS enrollment 
    FROM table1 AS gl 
    RIGHT OUTER JOIN table 2 AS lb ON gl.building_key = lb.building_key 
    where gl.bus_name = 'Business' 
    and gl.year_cd = 2010 
    GROUP BY lb.building_code , lb.bus_code, gl.bus_name

來源

2013-04-05 17:51:02

回答

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