Python列表切片找不到輸入用'in'運算符

我目前正在做一些作業，我在其中加載了兩個文本文件，每個文件都帶有200個名稱，分成兩個不同的列表，一個男孩的名字和一個女孩的名字女孩的名字，因爲我還沒有完成男孩的名字）。我想要求用戶輸入一個名稱，然後顯示該名稱的流行程度。所以我使用切片將列表中的前50個名稱設置爲流行，並將最後50個名稱設置爲不流行。然而，在if語句中，無論輸入什麼內容，它總是會進入else子句。將boyList [0-51]設置爲popularBoys顯然有些問題，但我不確定是什麼，或者如何解決它。Python列表切片找不到輸入用'in'運算符

def main(): 
    openBoyFile = open('BoyNames.txt', 'r') 
    readBoyNames = openBoyFile.readlines() 
    openBoyFile.close() 

    boyList = [readBoyNames] 

    #remove \n 
    index = 0 
    while index < len(readBoyNames): 
     readBoyNames[index] = readBoyNames[index].rstrip('\n') 
     index += 1 

    print('Boy names: ', boyList) 


    openGirlFile = open('GirlNames.txt', 'r') 
    readGirlNames = openGirlFile.readlines() 
    openGirlFile.close() 

    girlList = [readGirlNames] 

    index2 = 0 
    while index2 < len(readGirlNames): 
     readGirlNames[index2] = readGirlNames[index2].rstrip('\n') 
     index2 += 1 

    print('') 
    print('Girl names: ', girlList) 



    popularBoys = boyList[0:51] 
    notSoPopularBoys = boyList[52:151] 
    totallyNotPopularBoys = boyList[152:200] 

    print('') 
    boyNameInput = input('Enter a boy name to check how popular it is: ') 

    if boyNameInput in popularBoys: 
     print('The name entered is among the 50 most popular!') 

    elif boyNameInput in notSoPopularBoys: 
     print('The name entered is not so pouplar. Among 51 - 150 on the list.') 

    elif boyNameInput in totallyNotPopularBoys: 
     print('The name entered is not popular at all. Among 151-200 on the list.') 

    else: 
     print('Not a name on the list.') 


main()

來源

2014-12-20 Egekilde

根據您的描述，這不可能是您的問題，但請注意Python切片'[a：b]'返回索引在'a'的元素直到幷包括'b-1'，而不是'b '。 – xnx

問題是這兩行：

boyList = [readBoyNames] 
girlList = [readGirlNames]

readBoyNames和readGirlNames已經列出。您正在創建一個包含另一個列表的列表。如果更改這兩個行

boyList= readBoyNames 
girlList= readGirlNames

它的工作原理，沒有任何問題。

來源

2014-12-20 13:24:14

Python列表切片找不到輸入用'in'運算符

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