2013-02-02 139 views
6

我試圖讓json4s提取的東西,但我得到一個 「未知錯誤」JSON4S未知錯誤

我的代碼如下所示:

import org.json4s._ 
import org.json4s.jackson.JsonMethods._ 
implicit val formats = org.json4s.DefaultFormats 

case class Person(name: String, age: Int) 
val json = """{"name":"joe","age":15}""" 

print(parse(json).extract[Person]) 

錯誤路徑:

org.json4s.MappingException: unknown error 
    at org.json4s.Extraction$.extract(Extraction.scala:50) 
    at org.json4s.ExtractableJsonAstNode.extract(ExtractableJsonAstNode.scala:21) 
    at Main$$anon$1.<init>(test.scala:8) 
    at Main$.main(test.scala:1) 
    at Main.main(test.scala) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) 
    at java.lang.reflect.Method.invoke(Method.java:597) 
    at scala.tools.nsc.util.ScalaClassLoader$$anonfun$run$1.apply(ScalaClassLoader.scala:78) 
    at scala.tools.nsc.util.ScalaClassLoader$class.asContext(ScalaClassLoader.scala:24) 
    at scala.tools.nsc.util.ScalaClassLoader$URLClassLoader.asContext(ScalaClassLoader.scala:88) 
    at scala.tools.nsc.util.ScalaClassLoader$class.run(ScalaClassLoader.scala:78) 
    at scala.tools.nsc.util.ScalaClassLoader$URLClassLoader.run(ScalaClassLoader.scala:101) 
    at scala.tools.nsc.ObjectRunner$.run(ObjectRunner.scala:33) 
    at scala.tools.nsc.ObjectRunner$.runAndCatch(ObjectRunner.scala:40) 
    at scala.tools.nsc.ScriptRunner.scala$tools$nsc$ScriptRunner$$runCompiled(ScriptRunner.scala:171) 
    at scala.tools.nsc.ScriptRunner$$anonfun$runScript$1.apply(ScriptRunner.scala:188) 
    at scala.tools.nsc.ScriptRunner$$anonfun$runScript$1.apply(ScriptRunner.scala:188) 
    at scala.tools.nsc.ScriptRunner$$anonfun$withCompiledScript$1.apply$mcZ$sp(ScriptRunner.scala:157) 
    at scala.tools.nsc.ScriptRunner$$anonfun$withCompiledScript$1.apply(ScriptRunner.scala:131) 
    at scala.tools.nsc.ScriptRunner$$anonfun$withCompiledScript$1.apply(ScriptRunner.scala:131) 
    at scala.tools.nsc.util.package$.waitingForThreads(package.scala:26) 
    at scala.tools.nsc.ScriptRunner.withCompiledScript(ScriptRunner.scala:130) 
    at scala.tools.nsc.ScriptRunner.runScript(ScriptRunner.scala:188) 
    at scala.tools.nsc.ScriptRunner.runScriptAndCatch(ScriptRunner.scala:201) 
    at scala.tools.nsc.MainGenericRunner.runTarget$1(MainGenericRunner.scala:58) 
    at scala.tools.nsc.MainGenericRunner.process(MainGenericRunner.scala:80) 
    at scala.tools.nsc.MainGenericRunner$.main(MainGenericRunner.scala:89) 
    at scala.tools.nsc.MainGenericRunner.main(MainGenericRunner.scala) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) 
    at java.lang.reflect.Method.invoke(Method.java:597) 
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120) 
Caused by: java.lang.NoSuchFieldException: MODULE$ 
    at java.lang.Class.getField(Class.java:1520) 
    at org.json4s.Meta$$anonfun$mappingOf$1$$anonfun$8.apply(Meta.scala:208) 
    at org.json4s.Meta$$anonfun$mappingOf$1.apply(Meta.scala:207) 
    at org.json4s.Meta$$anonfun$mappingOf$1.apply(Meta.scala:195) 
    at org.json4s.Meta$Memo.memoize(Meta.scala:240) 
    at org.json4s.Meta$.mappingOf(Meta.scala:195) 
    at org.json4s.Extraction$.mkMapping$1(Extraction.scala:207) 
    at org.json4s.Extraction$.org$json4s$Extraction$$extract0(Extraction.scala:214) 
    at org.json4s.Extraction$.extract(Extraction.scala:47) 
    ... 34 more 

我運行SCALA 2.9.2與json4s 2.9.2:3.1.0與傑克遜解析器2.1.1

在我去「json4s」之前,我tryed jackson di直接,並沒有得到提供的例子與提取工作,所以我想圖中的東西是在這裏,但不是一個線索從哪裏開始尋找線索。

預先感謝幫助:)

回答

0

我還沒有嘗試過,但常見問題解答部分@https://github.com/json4s/json4s提到:

「提取不適合在REPL定義的類工作編譯與本案類定義。並將其導入REPL。「

9

實際上,您放置案例分類代碼時存在差異。考慮兩個例子:

class SomeServlet { 
def someMethod(json: String) = parse(json).extract[Person] 
case class Person(name: String, age: Int) 
} 

在這種情況下類Person將與類型SomeServlet(如Java非靜態內部類)的隱式字段,因此將不對應於給定的JSON。這就是爲什麼你會得到一個異常。現在看第二個例子:

class SomeServlet { 
def someMethod(json: String) = parse(json).extract[Person] 
} 

case class Person(name: String, age: Int) 

在第二個例子中,類Person是完全獨立的,因此沒有隱式字段。所以它應該工作。至少爲我工作。

+0

偉大的答案。這可能會誤導那些剛剛入門Scala的人。謝謝。 @Oliver應該接受這個答案。 – Shrayas

+0

謝謝!這爲我節省了很多時間。 –

0

同樣的問題。問題在於你定義你的案例類!

樣品JSON輸入

$.ajax({ 
     type: 'POST', 
     url: '', 
     contentType: 'text/plain', 
     data: JSON.stringify(
     {"subject":emailTitle,"body":emailMessage.join('\n')} 
     ), 
     success: function(){ 
     } 
     })  


import org.json4s._  
import org.scalatra.json.JacksonJsonSupport  
class EmailServlet extends ScalatraServlet {  
    post("/contact") {  
    val emailObj =parse(request.body).extract[EmailMessage] 
    SampleEmailService.sendEmail( 
    Email(emailObj.subject , emailObj.body)  
    )  
"ok"  
}  

}

//Outside Servlet definition  
case class EmailMessage(subject:String,body:String)