在OS X中獲取CPU arch字符串（C，Cocoa）

Question

如何在OS X中使用標準C庫或Cocoa獲取CPU體系結構字符串？

Answer 1

uname(3)

Answer 2

這裏有一個作弊的方式排序：

#if defined(__i386__) 
    return "i386"; 
#elif defined(__x86_64__) 
    return "x86-64"; 
#elif defined(__arm__) 
    return "arm"; 
// etc... 
#else 
# error "Unknown architecture!" 
#endif 

這不是絕對必要的檢查在運行時，因爲有一個爲每個架構一個單獨的可執行映像。

Answer 3

從man 2 uname：

#include <sys/utsname.h> 

    int uname(struct utsname *buf); 

    uname() returns system information in the structure pointed to by buf. 
    The utsname struct is defined in 
    <sys/utsname.h>: 

     struct utsname { 
      char sysname[]; /* Operating system name (e.g., "Linux") */ 
      char nodename[]; /* Name within "some implementation-defined 
           network" */ 
      char release[]; /* OS release (e.g., "2.6.28") */ 
      char version[]; /* OS version */ 
      char machine[]; /* Hardware identifier */ 
     }; 

    The length of the arrays in a struct utsname is unspecified; 
    the fields are terminated by a null byte ('\0'). 

提示： uname -m輸出返回(struct utsname).machine。