從兩個不同的條件在一個查詢中獲取不同的值

Question

我需要有像結果如下

section_one | section_two 
56788    678 

，這是我寫有上述結果的查詢分別

Select count(*) as section_one from tableNew 
WHERE columnone LIKE %hjk% 

而且

Select count(*) as section_two from tableNew 
WHERE columnone NOT LIKE %hjk%; 

如何在一個查詢中組合這兩個並獲得如上所示的結果？

我想下面的東西，但似乎並沒有正常工作

select *, 
CASE 
WHEN columnone LIKE %hjk% THEN count(1) as section_one 
ELSE count(1) as section_two 
END 
from tableNew 
Group by tableid; 

是否有任何其他的方式，以及中都有一個代替的條件？ 任何幫助，這將是偉大的！

PS：也就是有任何其他方式以及檢查boolean條件等代替columnone LIKE %hjk%目標columnone IS NOT NULL

Answer 1

試試這個使用SUM

select 
SUM(columnone LIKE %hjk%) as section_one, 
SUM(columnone NOT LIKE %hjk%) as section_two 
from tableNew 
Group by tableid; 

或者你可以使用CASE

select 
SUM(CASE WHEN columnone LIKE %hjk% THEN 1 ELSE 0 END) as section_one, 
SUM(CASE WHEN columnone NOT LIKE %hjk% THEN 1 ELSE 0 END) as section_two 
from tableNew 
Group by tableid;