從sql表中選擇銷售額最高的日期

Question

select max(total), date 
from (select sum(total) as total, date as date 
     from canteen 
     group by date) as max 

我想購買的出售最高和從表中最高銷售日期。

我的查詢顯示此錯誤。

異常，錯誤代碼8120和SQLState S0001]柱「max.date」是 在選擇列表中無效的，因爲它不是在任一種 聚合函數或GROUP BY子句含有。

Answer 1

您可以使用order by，通過銷售降序設置您的數據並獲取第一行。

如果你想通過日期的結果，那麼你可以使用ROW_NUMBER（）

select TOP(1) total, date 
from 
(
    select sum(total) as total, date as date 
    from canteen 
    group by date 
) as max 
Order by todal desc 

Answer 2

這將返回所有日期實現最大銷售總量。 Here是一個演示。

; with x as (
    select sum(total) as total, date from canteen group by date 
) 
, y as (
    select dr = dense_rank() over(order by total desc), * 
    from x 
) 
select * from y where dr = 1 

Answer 3

如果你想獲得的所有日期，最大（總），這裏是

;with temp as 
(
    select sum(total) as total, date as date 
    from canteen 
    group by date 
) 
SELECT TOP 1 WITH TIES * 
FROM temp 
ORDER BY temp.total desc 

Answer 4

你忘了通過&爲了通過在外部查詢添加組。我已將其修改爲以降序顯示所有銷售額。所以最高的銷售額將是最高的。

select max(total) total, date 
from (select sum(total) as total, date as date 
     from canteen 
     group by date) as max 
group by date 
order by total desc