2010-10-11 147 views
1

我正在使用下面的PHP腳本進行實驗,但它似乎錯誤地顯示錯誤消息:「字段列表中的未知列'time_submit109' 「當它進入數字跨度任務(在第110頁左右)。如何解決這個錯誤(我不熟悉PHP,所以我很難調試這個)。我認爲這個錯誤與time_submit1變量有關。'字段列表'中的未知列'time_submit109'

<?php 
//counter for dynamic timestamp and next_page 
$counter_page = ++$counter+1; 

//connect to db server 
mysql_connect($host,$user,$password) or die('Unable to connect to database server<br>'.mysql_error()); 

    //if this is the first page of a survey 
    if (!isset ($identification)) 
    //create db, if not already there 
    { 
    mysql_query("CREATE DATABASE IF NOT EXISTS $database"); 
    } 

//select db 
mysql_select_db($database) or die('Unable to select database<br>'.mysql_error()); 

    if (!isset ($identification)) 
    { 
    //create table, if not already there 
    mysql_query ("CREATE TABLE $table (identification int(9) NOT NULL auto_increment, 
    page1 TEXT, participation_date DATE, time_submit1 VARCHAR(8), ip_number VARCHAR(15), 
    browser TINYTEXT, PRIMARY KEY (identification)) TYPE=MyISAM"); 
    } 

     //change array, so that time_submit and page are renamed dynamically 
     foreach($variablen as $name=>$value) 
     { 
      if ($name == "next_page") 
      { 
      $name = "page".$counter_page; 
      } 
      elseif ($name == "counter") 
      { 
      $name = "time_submit".$counter; 
      $value = date("G:i:s"); 
      } 
     $newarray2[$name]=$value; 
     } 

    $variablen = $newarray2; 

     //for each line in the array of submitted variables do the following (traverse array) 
     foreach($variablen as $name=>$value) 
     {  
     //modify table step by step (add colums according to html input) 
     mysql_query ("ALTER TABLE $table ADD $name VARCHAR(255)"); 
     } 

     if (!isset ($identification))   
     { 
     //insert new record into db table (into the referer field) and thus generate identifcation (new record) 
     mysql_query("INSERT INTO $table (page1, participation_date, time_submit1, ip_number, browser) 
     VALUES ('$referer', '".date("Y-m-d")."', '".date("G:i:s")."', 
     '".$_SERVER['REMOTE_ADDR']."', '".$_SERVER['HTTP_USER_AGENT']."')")or die('Unable to insert into table!<br>'.mysql_error()); 
     //grab last value of auto-increment variable "identification" to be used as identifier 
     $identification = mysql_insert_id(); 
     } 

     //for each line in the array of submitted variables do the following 
     foreach($variablen as $name=>$value)  
     { 
     //update db table step by step 
     mysql_query("UPDATE $table SET $name='".mysql_real_escape_string($value)."' WHERE identification=$identification") or die('Unable to update table1<br>'.mysql_error()); 
     } 

    //close connection 
    mysql_close(); 

    //if this is the last html page: feedback for the participant 
    if (!isset ($next_page)) 
    { 
    echo $thank_you_text; 
    } 

    //if questionnaire consists of still another html page 
    else 
    { 
    //call up next HTML page and pass on ID and counter 
    echo "<html><head></head><body onLoad=\"javascript:location.replace('".$next_page."?op56=".$identification."&nr93=".$counter."')\"> 
    <a href=\"".$next_page."?op56=".$identification."&nr93=".$counter."\">Next Page</a></body></html>"; 
    //manual forwarding 
    //echo "<html><head></head><body><a href=\"".$next_page."?op56=".$identification."&nr93=".$counter."\">Next Page</a></body></html>"; 
    } 
?> 
+1

這真的需要'tl; dr' – RedFilter 2010-10-11 19:56:54

+0

這是怎麼回事?我試圖將其縮小到我認爲問題所在的地方。它必須與time_submit1變量以及它的更改方式有關嗎? – Victor 2010-10-11 20:02:52

+0

腳本結束後,表格的外觀如何?什麼是失敗的查詢? – Ishtar 2010-10-11 20:04:40

回答

0

不是一個真正的解決方案,但問題是指出您引用的字段名稱不是表的一部分。檢查數組並確保字段名稱確實存在於表格中

+0

我認爲這實際上導致我走下了這條道路。我很擔心創建另一列,因爲我必須爲每個後續列都這樣做,但它導致我發現根本原因可能是(http://dev.mysql.com/doc/refman/5.0/en/column -count-limit.html)。考慮到我的大量列是varchar(255),你認爲這可能是原因嗎?如果是這樣,我應該減少varchar計數? – Victor 2010-10-13 23:52:13

+0

修正了這個問題!我將ALTER TABLE $ table ADD $ name VARCHAR(255)更改爲ALTER TABLE $ table ADD $ name TEXT – Victor 2010-10-14 23:35:00

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