0
嗨，這實際上是在另一個問題（HERE），它有兩個部分。第一部分是通過@epascarello解決的 - 再次感謝，現在只剩下這部分了，我似乎沒有得到它。可複製的複選框只返回原始值不重複
我創建了一個可複製div的複選框，在提交時，它僅在控制檯中返回一個原始輸入值，但沒有任何重複值。
任何幫助非常感謝。
JS小提琴：http://jsfiddle.net/dawidvdh/EEd7c/
的jQuery：
//Clone Tracking
var g_counter = 1;
var d_counter = 1;
var dependant = ["dependant"];
var group;
//Clone Tracking
//General Variables
var relation_input_groups = ["relation-group-1"];
//General Variables
//Generate variables
var relation_fields=[0];
var relation_input ="<label>Spouse</label>"+
"<input type='checkbox' value='spouse' class='relationship' name='relationship' />" +
"<label>own child</label>"+
"<input type='checkbox' value='ownchild' class='relationship' name='relationship' />" +
"<label>adopted</label>"+
"<input type='checkbox' value='adopted' class='relationship' name='relationship' />" +
"<label>stepchild</label>"+
"<input type='checkbox' value='stepchild' class='relationship' name='relationship' />" +
"<label>parent</label>"+
"<input type='checkbox' value='parent' class='relationship' name='relationship' />" +
"<label>inlaw</label>"+
"<input type='checkbox' value='inlaw' class='relationship' name='relationship' />" +
"<label>brother</label>"+
"<input type='checkbox' value='brother' class='relationship' name='relationship' />" +
"<label>other</label>"+
"<input type='checkbox' value='other' class='relationship' name='relationship' />";
//Generate variables
jQuery(document).ready(function(e) {
//populate jquery generated fields
jQuery(relation_fields).each(function() {
jQuery(relation_input).appendTo('#relation-group-1');
});
//populate jquery generated fields
//Cloning Function
jQuery('#clone').click(function() {
clone_dependant();
});
function clone_dependant() {
// Store the value of the previous Id to insert the cloned div..
var oldId = g_counter;
g_counter++;
currentdep ='dependant-'+g_counter;
// Clone the Dependant Div and set a new id
var $clonedDiv = jQuery('#dependant-1').clone(false).attr('id', 'dependant-'+g_counter);
var relation_newDiv = 'relation-group-'+ g_counter;
// Find div's inside the cloned object and set a new id's
$clonedDiv.find('#relation-group-1').attr('id',"relation-group-" + g_counter);
// You don't need to Loop thru the inputs to set the value
$clonedDiv.find('input').val('');
$clonedDiv.find('input:checkbox').removeAttr('checked');
// Insert the cloned object
$clonedDiv.insertAfter("#dependant-" + oldId);
relation_input_groups.push(relation_newDiv);
}
//Cloning Function
//Validation
//submit function
$(document).on("click", 'input[type="checkbox"]', function() {
jQuery(this).siblings(":checked").removeAttr('checked');
});
var result = {};
var dependants;
var dep_counter = 0;
jQuery('#submit').click(function(){
jQuery('.dependant').each(function(k, v){
dep_counter++
dependants = {};
result['dependant'+dep_counter] = [dependants];
dependants['relationship'] = $(v).find('.relationship:checked').val();
});
var jsonData = JSON.stringify(result);
console.log(jsonData);
});
});
和HTML：
<div id="dependant-1" class="dependant">
<div id="label">relationship:</div> <div id="relation-group-1"></div>
</div>
<button id="clone">clone</button>
<button id="submit">submit</button>
嘿，不知道這是否合適，但你的答案通常是平靜的輝煌，你可以檢查一下：http://stackoverflow.com/questions/14374324/jquery-clone-able-inputs-foreach-overwrites-值/ –