1
下面是我的代碼,我試圖讓它顯示順序的結果,但是我不能讓它出現,我相信複選框的返回值可能不是真實的,所以我嘗試使用var checkedt5 = $("t5").is(':checked');
,但我得到onclick on order不起作用的錯誤。我相信這是功能上的錯誤。HTML複選框返回值?
<html>
<head>
<title>Form </title>
<script LANGUAGE="JavaScript">
<!-- hide from uneducated browsers
function Order()
{
var size = document.getElementById("pizzasize").value
var crust = document.getElementById("pizzacrust").value
var t1 = document.getElementById("t1").value
var t2 = document.getElementById("t2").value
var t3 = document.getElementById("t3").value
var t4 = document.getElementById("t4").value
var t5 = document.getElementById("t5").value
var checkedt1 = $("t1").is(':checked');
var checkedt2 = $("t2").is(':checked');
var checkedt3 = $("t3").is(':checked');
var checkedt4 = $("t4").is(':checked');
var checkedt5 = $("t5").is(':checked');
document.write("<p>")
document.write("Your order is in process <br /> ")
document.write("Pizza Size = " + size + "<br />")
document.write("Pizza Crust = " + crust + "<br />")
if (checkedt1 == true)
{
document.write("Toppings = " + t1 + "<br />")
}
if (checkedt2 == true)
{
document.write("Toppings = " + t2 + "<br />")
}
if (checkedt3 == true)
{
document.write("Toppings = " + t3 + "<br />")
}
if (checkedt4 == true)
{
document.write("Toppings = " + t4 + "<br />")
}
if (checkedt5 == true)
{
document.write("Toppings = " + t5 + "<br />")
}
document.write("Your order will be delivered as soon as possible")
return ""
}
// end hiding from uneducated browsers -->
</script>
<style TYPE="text/css">
body
{
background-color: lightsteelblue;
}
</style>
</head>
<body>
<h1>Mateo's Pizzeria</h1>
<form>
<b>Pizza Size</b>:
<select name="pizzasize" id="pizzasize">
<option value="" disabled="disabled" selected="selected">Please select a size</option>
<option value="personal">Personal</option>
<option value="small">Small</option>
<option value="medium">Medium</option>
<option value="large">Large</option>
<option value="x-large">X-Large</option>
<option value="omg">OMG</option>
</select>
<p>
<b>Pizza Crust</b>:
<select name="pizzacrust" id="pizzacrust">
<option value="" disabled="disabled" selected="selected">Please select a crust type</option>
<option value="thin">Thin</option>
<option value="thick">Thick</option>
<option value="sicilian">Sicilian</option>
</select>
<p>
<b>Pizza Toppings</b>:
<br>
<input type="checkbox" name="toppings" id="t1" value="pepperoni">Pepperoni<br>
<input type="checkbox" name="toppings" id="t2" value="sausage">Sausage<br>
<input type="checkbox" name="toppings" id="t3" value="mushrooms">Mushrooms<br>
<input type="checkbox" name="toppings" id="t4" value="black-olives">Block Olives<br>
<input type="checkbox" name="toppings" id="t5" value="pineapple">Pineapple<br>
</select>
<p>
<b>Confirmed Order</b>: <output TYPE="text" NAME="output" ID="outputID" SIZE="50" WIDTH="50" />
</p><p>
<input TYPE="button" VALUE="Confirm Order" onClick="Order()" />
</p><p>
<!--// <input TYPE="button" VALUE="Process Input 2" onClick="newProcess()" /> -->
</p></form>
</body>
</html>
我已經加入#到每個所要求的要素,但是,我仍然無法運行 – user2951224
@ user2951224包括jQuery的在你的頁面。 – Musa
@Musa會不會這樣工作? – user2951224