C++保存記錄到文件

Question

我一直在思考如何做到這一點「保存到文件」的事情了一夜，但似乎就在我身邊運氣wasnt ..。 我對此很陌生，而且我想學習，那就是所有。 我來自保加利亞，對於那些想知道什麼是「edinen」的人，這是您的公民號碼，作爲該國的成員。 （我仍然不知道如何解釋這個...）

這裏是我有什麼 （我已經包括了「fstream的」，但我仍然不知道如何使用它！

#include <iostream> 
#include <stdlib.h> 
#include <fstream> 
using namespace std; 
#define n 30 
int num=0; 
struct uslugi 
{ 
    char name[30]; 
    char surname[30]; 
    char lastname[30]; 
    char illness[30]; 
    long int edinen; 
}grupa[n]; 
void add_record(); 
void show_record(); 
void search_record(); 
void remove_record(); 
void add_record() // FUNCTION - ADD RECORD(S) 
{ 
    system("title Add Record"); 
    int br; 
    cout<<"\n How many pacients do you want to enter?"; 
    cout<<"\n >> "; 
    cin>>br; 
    for(int i=num;i<num+br;i++) 
    { 
     cout<<"\n \t\t ENTERING DATA FOR PACIENT NUMBER - "<<i+1<<endl; 
     cout<<"\n Name:"; 
     cout<<"\n >> "; 
     cin>>grupa[i].Name; 
     cout<<"\n Surname:"; 
     cout<<"\n >> "; 
     cin>>grupa[i].surname; 
     cout<<"\n Lastname:"; 
     cout<<"\n >> "; 
     cin>>grupa[i].lastname; 
     cout<<"\n edinen:"; 
     cout<<"\n >> "; 
     cin>>grupa[i].edinen; 
     cout<<"\n Ill from:"; 
     cout<<"\n >> "; 
     cin>>grupa[i].illness; 
    } 
    num=num+br; 
} 
void show_record() // FUNCTION - SHOW RECORD(S) 
{ 
    if (num==0) 
    { 
     cout<<"\t\t by far there are no pacient at all \n"; 

    } 
    cout<<"\n \t\t\t list with all pacients"<<num<<endl; 
    for(int i=0;i<num;i++) 
    { 
    cout<<"\n Name:"; 
    cout<<"\n >> "<<grupa[i].name; 
    cout<<"\n Surname:"; 
    cout<<"\n >> "<<grupa[i].surname; 
    cout<<"\n Lastname:"; 
    cout<<"\n >> "<<grupa[i].lastname; 
    cout<<"\n edinen:"; 
    cout<<"\n >> "<<grupa[i].edinen; 
    cout<<"\n Ill from:"; 
    cout<<"\n >> "<<grupa[i].illness; 
    cout<<"\n\n"; 

    } 
} 
void remove_record() // FUNCTION - DELETE RECORD(S) 
{ 
    int k,index; 
    for(int i=0;i<num;i++) 
    { 
    cout<<"\n("<<i+1<<") "<<endl; 
    cout<<"Pacient name: "<<grupa[i].name<<endl; 
    cout<<"Surname: "<<grupa[i].surname<<endl; 
    cout<<"Lastname: "<<grupa[i].lastname<<endl; 
    cout<<"edinen: "<<grupa[i].edinen<<endl; 
    cout<<"Ill from: "<<grupa[i].illness<<endl<<endl; 
    } 
    cout<<"Who do you want to delete? \n >> "; 
    cin>>index; 
    for(k=0;k<num;k++) 
    { 
     if(k>=index) 
     { 
      grupa[k].edinen=grupa[k+1].edinen; 
     } 
     if(k==num-1) 
      break; 
     else 
      cout<<"BY FAR THERE IS NO DATA HERE"<<endl; 
    } 
    num--; 

     for (i=0;i<num;i++) 
    { 
    cout<<"Pacient name: "<<grupa[i].name<<endl; 
    cout<<"Surname: "<<grupa[i].surname<<endl; 
    cout<<"Lastname: "<<grupa[i].lastname<<endl; 
    cout<<"edinen: "<<grupa[i].edinen<<endl; 
    cout<<"Ill from: "<<grupa[i].illness<<endl<<endl; 
    } 
} 
void print_count() // FUNCTION - PRINTING 
{ 
    cout<<"\n \t\t\t NUMBER OF PACIENTS - "<<num<<endl; 
    cout<<""<<endl; 
} 


void search_record() // FUNCTION - SEARCHING 
{ 
    int flag=0; 
    long int tempegn; 
    cout<<"\n Type the edinen for the pacient you search: "; 
    cout<<"\n >> "; 
    cin>>tempegn; 
    for (int i=0;i<n;i++) 
     if(tempegn==grupa[i].edinen) 
     { 
    cout<<"Pacient name: "<<grupa[i].name<<endl; 
    cout<<"Surname: "<<grupa[i].surname<<endl; 
    cout<<"Lastname: "<<grupa[i].lastname<<endl; 
    cout<<"edinen: "<<grupa[i].edinen<<endl; 
    cout<<"Ill from: "<<grupa[i].illness<<endl<<endl; 
      flag++; 
     } 
     if (!flag) 
     { 
      cout<<"\n\t PACIENT WITH THAT NAME DOESNT EXCIST \n\n"; 
     } 
} 

void main() // MAIN FUNCTION (MENU) 
{ 
    int choice; 
    do 
    { 
     cout<<"\n\t\t******************* Menu *******************"<<endl; 
     cout<<"\t\t*            *"; 
     cout<<"\n\t\t*   1.Add new pacient     *"; 
     cout<<"\n\t\t*   2.Search for a pacient by edinen *"; 
     cout<<"\n\t\t*   3.Delete pacient     *"; 
     cout<<"\n\t\t*   4.List with all pacients   *"; 
     cout<<"\n\t\t*   5.Exit        *"; 
     cout<<"\n\t\t*            *\n"; 
     cout<<"\t\t************************************************"<<endl; 
     cout<<"\n Type your choice! "; 
     cout<<"\n >> "; 
     cin>>choice; 
     switch(choice) 
     { 
     case 1:{print_count();add_record();break;} 
     case 2:{print_count();search_record();break;} 
     case 3:{print_count();remove_record();break;} 
     case 4:{print_count();show_record();} 
     } 
    } 
    while(choice!=5); 
} 

Answer 1

我建議你讀一本書，或者至少有一些關於此文檔。此外，要了解這種投入的工作，它需要的OOP概念知識。至於我注意到你沒有這樣的知識，我建議你堅持一段時間，使用C的程序I/O函數，比如fprintf。谷歌搜索會顯示很多關於它們的資源，並且它們很容易理解，至少與那些來自C++的相比，正在使用

要回答你的問題，我會盡量解釋如何才達到你想要什麼。請注意，這是一個非常簡單的解釋，並非100％準確。

首先，需要打開該文件並創建一個I/O流中，使用用於ifstream輸入文件或ofstrsam輸出文件：

ifstream的F（ 「input_filename」）;

的ofstream克（「output_filename）;

創建f和/或g之後（他們是不是都科目編號另外，f和g只是隨機的名字），你可以在你用同樣的方法使用它們cin和cout，在這種情況下，因爲f是輸入，所以它應該像cin一樣使用。