獲取屬於一個組的用戶數

-1

我有以下三個表，成員，ageGroup和日誌。我想知道每個年齡組有多少人在特定的時間內訪問系統。下面是表的詳細信息獲取屬於一個組的用戶數

tblMembers：

Member_Id，出生日期，年齡

tblAgeGroup：

AgeGroup標識，AgeGroup_Des，MINAGE，MAXAGE，meanAge

tblLog：

Member_Id，AccessDate

所以當管理員選擇一個時間範圍，如2014年1月4日於30/04/2014

我需要示出了類似於下面的輸出：

AgeGroup用戶

15-25 -------------- 3

25-35 -------------- 2

的無

我怎麼都無法這樣做。下面是我根據劇本迄今所做

SELECT Member_Id, Age 
    FROM tblLog 
     JOIN tblMembers ON tblMembers.Member_Id = tblLog.Member_Id 
    WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30' 
    GROUP BY Member_Id, Age

，我能列出Members_Id和他們的年齡。我如何通過在tblAgeGroup表中找到的組詳細信息進行分組。

請指教我。謝謝

來源

2014-05-12 M.A

您使用的是哪種數據庫平臺？ MySQL或SQL Server？ –

當您運行該查詢時會發生什麼？ –

@PatrickHofman我正在使用MSSQL –

嘗試

SELECT ag.AgeGroup_Des, count(1) 
    FROM tblLog l 
     INNER JOIN tblMembers m ON m.Member_Id = l.Member_Id 
     INNER JOIN tblAgeGroup ag ON ag.minAge <= m.Age and ag.maxAge > m.Age 
    WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30' 
    GROUP BY ag.AgeGroup_Des

然而，使用間隔，因爲我們在這裏做的tblAgeGroup加入時，它來測試我們得到正確的行數是很重要的。

所以我會運行下面的查詢，並驗證他們確實做返回相同的行數：

SELECT COUNT(1) 
    FROM tblLog l 
     INNER JOIN tblMembers m ON m.Member_Id = l.Member_Id 
     --INNER JOIN tblAgeGroup ag ON ag.minAge <= m.Age and ag.maxAge > m.Age 
    WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30'

和

SELECT COUNT(1) 
    FROM tblLog l 
     INNER JOIN tblMembers m ON m.Member_Id = l.Member_Id 
     INNER JOIN tblAgeGroup ag ON ag.minAge <= m.Age and ag.maxAge > m.Age 
    WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30'

有跡象表明，我想起兩兩件事，在這裏使用間隔時可能會出錯。

首先;如果間隔沒有唯一定義，則每個成員都會返回幾次。如考慮含 ... ，MINAGE = 15 ，MAXAGE = 35 ... 和另一個條目tblAgeGroup： ... ，MINAGE = 20 ，MAXAGE = 25 ...

與21年齡將因此在這兩個區間得到恢復，從而在數量製造通貨膨脹的成員。

其次;如果Age未在tblMembers中定義，則該行將被排除，但這可能是有意的，因爲我們正在使用內部聯接。你可以解決這個問題，有以下幾點：

SELECT ISNULL(ag.AgeGroup_Des, 'No group found') as AgeGroup_Des, 
     COUNT(1) as "AMT users" 
    FROM tblLog l 
     INNER JOIN tblMembers m ON m.Member_Id = l.Member_Id 
     LEFT JOIN tblAgeGroup ag ON ag.minAge <= m.Age and ag.maxAge > m.Age 
    WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30' 
    GROUP BY ISNULL(ag.AgeGroup_Des, 'No group found') 
    ORDER BY 1

編輯： 增加了SQLFiddle測試： http://sqlfiddle.com/#!6/137b8/5

查詢的小提琴是：

體形：

CREATE TABLE tblMembers 
(
    Member_ID int, 
    DOB date, 
    Age int 
); 

CREATE TABLE tblAgeGroup 
(
    [AgeGroup Id] int, 
    AgeGroup_Des varchar(16), 
    minAge int, 
    maxAge int, 
    meanAge float 
); 

CREATE TABLE tblLog 
(
    Member_id int, 
    AccessDate date 
); 



INSERT INTO tblMembers 
     (Member_ID, DOB, Age) 
SELECT 1, '1991-03-22', 23 
UNION ALL 
SELECT 2, '2000-03-22', 14 
UNION ALL 
SELECT 3, '1981-03-22', 33 
UNION ALL 
SELECT 4, null, null; 

INSERT INTO tblAgeGroup 
     ([AgeGroup Id], AgeGroup_Des, minAge, maxAge, meanAge) 
SELECT 1, '15-25', 15, 25, null 
UNION ALL 
SELECT 2, '10-15', 10, 15, null 
UNION ALL 
SELECT 3, '25-55', 25, 55, null; 

INSERT INTO tblLog 
     (Member_id, AccessDate) 
SELECT 1, GETDATE() 
UNION ALL 
SELECT 2, GETDATE() 
UNION ALL 
SELECT 1, '2014-04-02' 
UNION ALL 
SELECT 2, '2014-04-03' 
UNION ALL 
SELECT 2, '2014-04-03' 
UNION ALL 
SELECT 3, '2014-04-03' 
UNION ALL 
SELECT 4, '2014-04-03';

查詢：

-- First query: (exludes member 4, since no DOB is registered: 
SELECT ag.AgeGroup_Des, COUNT(1) 
    FROM tblLog l 
     INNER JOIN tblMembers m ON m.Member_Id = l.Member_Id 
     INNER JOIN tblAgeGroup ag ON ag.minAge <= m.Age and ag.maxAge > m.Age 
    WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30' 
    GROUP BY ag.AgeGroup_Des; 

-- To validate that the counts are the same: 
SELECT COUNT(1) 
    FROM tblLog l 
     INNER JOIN tblMembers m ON m.Member_Id = l.Member_Id 
     --INNER JOIN tblAgeGroup ag ON ag.minAge <= m.Age AND ag.maxAge > m.Age 
    WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30'; 

-- Second validation: 
-- Notice: this does return one less row, since we are using inner join, 
-- and thus ommitting member 4 
SELECT COUNT(1) 
    FROM tblLog l 
     INNER JOIN tblMembers m ON m.Member_Id = l.Member_Id 
     INNER JOIN tblAgeGroup ag ON ag.minAge <= m.Age AND ag.maxAge > m.Age 
WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30'; 

-- Last query, which includes members with no DOB registered, 
-- as well as members that does not fall into any group: 
SELECT ISNULL(ag.AgeGroup_Des, 'No group found') as AgeGroup_Des, 
     COUNT(1) as "AMT users" 
    FROM tblLog l 
     INNER JOIN tblMembers m ON m.Member_Id = l.Member_Id 
     LEFT JOIN tblAgeGroup ag ON ag.minAge <= m.Age AND ag.maxAge > m.Age 
    WHERE AccessDate >= '2014-04-01' 
    AND AccessDate <= '2014-04-30' 
    GRUOP BY ISNULL(ag.AgeGroup_Des, 'No group found') 
    ORDER BY 1;

2014年5月14日：編輯：

我在您的意見看，你還需要爲空組計數。爲了做到這一點，我已經「倒置」了from子句，以便我們從tblAgeGroup中選擇所有，然後左加入其他表。

此外，我認爲你需要一些日誌條目，但在閱讀評論後，我看到你要求不同的用戶。我已經相應地更改了查詢。

select 
    ag.AgeGroup_Des 
, count(l.Member_ID)   as [AMT Log entries] 
, count(distinct l.Member_ID) as [AMT distinct members] 
from tblAgeGroup ag 
left join tblMembers m on ag.minAge <= m.Age and ag.maxAge > m.Age 
left join tblLog l on l.Member_id = m.Member_ID 
group by isnull(ag.AgeGroup_Des, 'No group found') 
order by 1 
;

AgeGroup_Des AMT Log entries AMT distinct members 
10-15    3    1 
15-25    2    1 
25-55    1    1 
55-65    0    0

然而，這種方法確實會忽略不具有DOB /年齡登記的每一個成員。如果我們要包括這些藏漢，我們需要編輯查詢到完全外部聯接：

select 
    isnull(ag.AgeGroup_Des, 'No group found') as AgeGroup_Des 
, count(l.Member_ID)   as [AMT Log entries] 
, count(distinct l.Member_ID) as [AMT distinct members] 
from tblAgeGroup ag 
full outer join tblMembers m on ag.minAge <= m.Age and ag.maxAge > m.Age 
full outer join tblLog l on l.Member_id = m.Member_ID 
group by isnull(ag.AgeGroup_Des, 'No group found') 
order by 1 
;

AgeGroup_Des AMT Log entries AMT distinct members 
10-15    3    1 
15-25    2    1 
25-55    1    1 
55-65    0    0 
No group found  1    1

見更新小提琴這裏：http://sqlfiddle.com/#!6/d8733/5

來源

2014-05-12 08:20:42

當我運行你發佈的第一個腳本我得到0條記錄。 –

@GunnarKundsen，但是你的第二個腳本指示了2301條記錄，第三個腳本指向了0條記錄。我可以知道這是爲什麼嗎？ –

不知道你的數據集，我不能說這是爲什麼，但我已經創建了一些測試數據，查詢按預期執行，看到這個小提琴：http://sqlfiddle.com/#!6/137b8/ 5（我也編輯過這個答案）。你的數據集有何不同？ –

SELECT usr_type, SUM(_15_25 + _25_35) AS qty 
    FROM 
     (SELECT CASE 
        WHEN age>=15 AND age<25 THEN '15-25' 
        WHEN age>=25 AND age<=35 THEN '25-35' 
        ELSE 'other' 
       END AS usr_type, 
       CASE 
        WHEN age>= 15 AND age < 25 THEN 1 
        ELSE 0 
       END AS _15_25, 
       CASE 
        WHEN age >= 25 AND age <= 35 THEN 1 
        ELSE 0 
       END AS _25_35 
       Age 
      FROM tblLog 
       JOIN tblMembers ON tblMembers.Member_Id = tblLog.Member_Id 
      WHERE AccessDate >= '2014-04-01' 
      AND AccessDate <= '2014-04-30' 
     ) T 
    GROUP BY usr_type

試試這個邏輯解決方案。

來源

2014-05-12 08:14:06 realnumber3012

SELECT minAge, maxAge, count(*) as "No of Users" 
    FROM tblAgeGroup g 
     INNER JOIN tblMembers m ON Age BETWEEN minAge AND maxAge 
     INNER JOIN tblLog l ON m.Member_ID = l.Member_ID 
    WHERE AccessDate BETWEEN '2014-04-01' and '2014-04-30' 
    GROUP BY minAge, maxAge 
    ORDER BY minAge, maxAge

來源

2014-05-12 08:25:14 SaadH

獲取屬於一個組的用戶數

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