如何獲取多個選擇的結果併合併爲一行

我有一張包含4個發電機信息的表我想將四個查詢的結果放在一行中。有沒有人有一個建議。由於如何獲取多個選擇的結果併合併爲一行

SELECT avg(KW) as GEN_101_AVG 
FROM   genset WHERE  (GenSetName like 'GEA3519') and GenDate >= '1 jan 2003 00:00:00' and GenDate < '1 feb 2003 00:00:00' 

    SELECT avg(KW) as GEN_201_AVG 
FROM   genset WHERE  (GenSetName like 'GEA3520') and GenDate >= '1 jan 2003 00:00:00' and GenDate < '1 feb 2003 00:00:00' 

SELECT avg(KW) as GEN_301_AVG 
FROM   genset WHERE  (GenSetName like 'GEA3521') and GenDate >= '1 jan 2003 00:00:00' and GenDate < '1 feb 2003 00:00:00' 

SELECT avg(KW) as GEN_401_AVG 
FROM   genset WHERE  (GenSetName like 'GEA3522') and GenDate >= '1 jan 2003 00:00:00' and GenDate < '1 feb 2003 00:00:00'

MS-SQL

來源

2009-06-08 Brad

請使用 'SQLSERVER' 的標籤，而不是 'MSSQL'。在標記問題時請注意建議：名稱後小於10的任何標籤可能是錯誤的。在這種情況下，有超過5000個標籤爲'sqlserver'的問題和零標籤'msssql'。 – 2009-06-08 14:35:43

不知道爲什麼我得到了否決票 – Brad 2009-06-08 14:36:53

備案：不是我。 – 2009-06-08 15:06:08

SELECT (
     SELECT avg(KW) 
     FROM genset 
     WHERE (GenSetName like 'GEA3519') 
       and GenDate >= '1 jan 2003 00:00:00' 
       and GenDate < '1 feb 2003 00:00:00' 
     ) AS avg_GEA3519, 
     (
     SELECT avg(KW) 
     FROM genset 
     WHERE (GenSetName like 'GEA3520') 
       and GenDate >= '1 jan 2003 00:00:00' 
       and GenDate < '1 feb 2003 00:00:00' 
     ) AS avg_GEA3520, 
     (
     SELECT avg(KW) 
     FROM genset 
     WHERE (GenSetName like 'GEA3521') 
       and GenDate >= '1 jan 2003 00:00:00' 
       and GenDate < '1 feb 2003 00:00:00' 
     ) AS avg_GEA3521, 
     (
     SELECT avg(KW) 
     FROM genset 
     WHERE (GenSetName like 'GEA3522') 
       and GenDate >= '1 jan 2003 00:00:00' 
       and GenDate < '1 feb 2003 00:00:00' 
     ) AS avg_GEA3522

，或者在SQL Server 2005+，這樣：

SELECT [GEA3519], [GEA3520], [GEA3521], [GEA3522] 
FROM (
     SELECT GenSetName, KW 
     FROM genset 
     WHERE GenDate >= '1 Jan 2003 00:00:00' 
       AND GenDate < '1 Feb 2003 00:00:00' 
     ) AS q 
PIVOT 
(
     AVG(KW) 
     FOR GenSetName IN (['GEA3519'], ['GEA3520'], ['GEA3521'], ['GEA3522'] 
)

來源

2009-06-08 14:34:11 Quassnoi

我的想法完全 - 雖然我會親自爲這些專欄加上別名。 – RichardOD 2009-06-08 14:37:32

作爲選擇的個數不限於四個，一種解決方案是選擇成變量，然後做最後的選擇。像下面這樣：

declare @var1 <TYPE> 
declare @var2 <TYPE> 
declare @var3 <TYPE> 
declare @var4 <TYPE> 

select @var1 = SELECT avg(...) ... 
select @var2 = ... 
select @var3 = ... 
select @var4 = ... 

select @var1 as ..., @var2 as ..., @var3 as ..., @var4 as ...

來源

2009-06-08 14:37:50

另一種選擇：

SELECT 
    AVG(GEN_101.kw) AS GEN_101_AVG, 
    AVG(GEN_201.kw) AS GEN_201_AVG, 
    AVG(GEN_301.kw) AS GEN_301_AVG, 
    AVG(GEN_401.kw) AS GEN_401_AVG 
FROM 
    Genset GEN_101 
INNER JOIN Genset GEN_201 ON 
    GEN_201.GenSetName = 'GEA3520' AND 
    GEN_201.GenDate >= '1 jan 2003 00:00:00' AND 
    GEN_201.GenDate < '1 feb 2003 00:00:00' 
INNER JOIN Genset GEN_101 ON 
    GEN_301.GenSetName = 'GEA3521' AND 
    GEN_301.GenDate >= '1 jan 2003 00:00:00' AND 
    GEN_301.GenDate < '1 feb 2003 00:00:00' 
INNER JOIN Genset GEN_101 ON 
    GEN_401.GenSetName = 'GEA3522' AND 
    GEN_401.GenDate >= '1 jan 2003 00:00:00' AND 
    GEN_401.GenDate < '1 feb 2003 00:00:00' 
WHERE 
    GEN_101.GenSetName = 'GEA3519' AND 
    GEN_101.GenDate >= '1 jan 2003 00:00:00' AND 
    GEN_101.GenDate < '1 feb 2003 00:00:00'

來源

2009-06-08 15:24:18

如何獲取多個選擇的結果併合併爲一行

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