排序根據另一單元陣列

Question

我有兩個單元陣列的單元陣列，

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}]; 
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}]; 

是否有MATLAB任何智能方式來排序數組2，相對於所述單元陣列的參考;

該函數應該返回array2的索引，其順序與「reference」的順序相同（array2將與參考相同）。

爲如

magic_order = function(array2, reference) 
.... 
end 

magic_order（數組2，參考）將返回

1,4,3,5,2 

，現在，如果我做

array2(1,4,3,5,2) 

我會得到相同的參考

排序功能

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}]; 
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}]; 
[a, b] = sort(reference) 
isequal(reference, array2(b)) 
ans = 0 

Answer 1

ismember的第二個輸出也可能有用。

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}]; 
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}]; 
[~, pos] = ismember(reference,array2); 

結果：

>> isequal(array2(pos),reference) 

ans = 

    1 

Answer 2

使用intersect：

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}]; 
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}]; 

[~, ~, idx] = intersect(reference, array2, 'stable'); 

將返回：

>> isequal(reference, array2(idx)) 

ans = 

    1 

的使用setOrder='stable'intersect（我已經忽略不計）的第一輸出，返回共同的價值觀reference和array2的順序與相同。第三個輸出是第一個輸出中的array2索引。假設單元陣列相等，這將是reference中array2的索引。