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定義的功能指針我正在使用一個框架,傳遞函數指針爲void*
。我想要一個模擬函數返回一個函數指針,並且我想定義函數就地(就像lambda;它不起作用,如下所示)。GMock:如何返回由EXPECT_CALL()
一個最小的工作示例如下所示。
#include <gtest/gtest.h>
#include <gmock/gmock.h>
using namespace std;
using namespace testing;
class Original
{
public:
typedef int(*fptr)();
void Func()
{
void* f = Func2();
fptr func = reinterpret_cast<fptr>(f);
if (func) {
int i = func();
if (i == 1) {
//do something
} else if (i == 3) {
//NOTE my unit test should test this decision branch
}
}
}
static int Func3() {return 1;}
virtual void* Func2() {return (void*)&Func3;}
};
class MyMock : public Original
{
public:
MOCK_METHOD0(Func2, void*());
};
我的主要目標:我想擺脫這個功能,並且在EXPECT_CALL()
內嵌定義它。見下文。
int MockFunc() {cout << "mock func" << endl; return 3;}
測試用例:
TEST(MYTEST, Test)
{
MyMock m;
//WORKS: compiles and works as expected,
//but I do not want to use **MockFunc**
EXPECT_CALL(m, Func2()).Times(AtLeast(1))
.WillRepeatedly(Return(&MockFunc));
//DOES NOT WORK: Does not compile, of course
//(compiler message below this code block)
EXPECT_CALL(m, Func2()).Times(AtLeast(1))
.WillRepeatedly(Return((void*)&([](){return 3;})));
m.Func();
}
main.cpp中:117:90:錯誤:服用的臨時[-fpermissive]
爲了完整起見,main()
地址:
int main(int argc, char** argv)
{
::testing::InitGoogleTest(&argc, argv);
return RUN_ALL_TESTS();
}
所以q再次問:我怎樣才能擺脫MockFunc()
函數,並在Return()
內就地定義它的內容?