我試圖從存儲SQL數據庫($演示)變量($ Q11),但我得到的錯誤注意:不明指標:俠諾在C:\ XAMPP htdocs中,
注意:不明指標:俠諾在C:\ XAMPP \ htdocs中\,......
請這個錯誤一些人給解決
<?php
$connect = mysql_connect("localhost","root","")
or die(mysql_error());
$sel=mysql_select_db("demo");
$query1 = mysql_query("SELECT * FROM `linuxq` ORDER BY RAND() LIMIT 10 ");
echo "<h4 align='Center'><u>Linux Questions</u><br></h4>";
$rows11 = mysql_fetch_array($query1);
$q11 = $rows11['QNo'];
$qus11 = $rows11['Question'];
$a = $rows11['Opt1'];
$b = $rows11['Opt2'];
$c = $rows11['Opt3'];
$d = $rows11['Opt4'];
$ans11 = $rows11['Ans'];
echo " <b>Question:-<br></b>$qus11 <br>";
echo " <input type=radio name = 'answer$q11' value = '$a'></input>$a    ";
echo " <input type=radio name = 'answer$q11' value = '$b'></input>$b    ";
echo " <input type=radio name = 'answer$q11' value = '$c'></input>$c     ";
echo " <input type=radio name = 'answer$q11' value = '$d'></input>$d <br><br> ";
使用while循環來打印數據,因爲你從數據庫中獲取10條記錄 – Khushboo 2014-09-27 10:48:25
http://siliconstation.com/how-fix-php-notice-undefined-index/ – mahen3d 2014-09-27 10:49:22
@Khushboo更多的if語句,如果他只喜歡一行... – bwoebi 2014-09-27 10:49:22