如何使用通過外鍵的Eloquent搜索查詢

Question

我試圖通過在列（patient_id）中搜索來在（預訂）表中搜索框，並且此列是（患者）表的外鍵，並且此列（patient_id）通過foreach {{$ booking-> patient-> patient_name}}獲取（patient_name）的數據，問題是我不知道如何通過（patient_id）在我的控制器（BookingController）中搜索（patient_name），任何幫助？對不起，我的語言:(

這是我的訂房控制器：

public function index() 
{ 
    $search = \Request::get('search'); 

    $bookings = Booking::with('patient')->where('status','=', null)- 
>where('patient_name','like', '%'. $search. '%')->paginate(10); 

    return view('booking.index')->withBookings($bookings); 
} 

我的預訂型號：

<?php 

namespace App; 

use Illuminate\Database\Eloquent\Model; 
use Eloquent; 

class Booking extends Eloquent 
{ 

public function patient() 
{ 
return $this->belongsTo('App\Patient'); 

} 
} 

我的患者模型：

<?php 

namespace App; 

use Illuminate\Database\Eloquent\Model; 
use Eloquent; 
class Patient extends Eloquent 
{ 
public function booking() 
{ 
return $this->hasMany('App\Booking'); 

} 
} 

修訂..This是索引頁

{!! Form::open(['method'=>'GET','url'=>'booking','class'=>'navbar-form navbar-left','role'=>'search']) !!} 
<a href="{{ url('booking.index') }}" class="btn btn-primary btn-sm"><span class="glyphicon glyphicon-plus"></span> Add</a> 

<div class="input-group custom-search-form"> 
    <input type="text" class="form-control" name="search" placeholder="Search..."> 
    <span class="input-group-btn"> 
     <button class="btn btn-default-sm" type="submit"> 
      <i class="fa fa-search"> <span class="hiddenGrammarError" pre="" data-mce-bogus="1"></span></i> 
     </button> 
    </span> 
</div> 
{!! Form::close() !!} 
      <th>حجز باسم</th> 
         <th>القيمة</th> 
         <th>اسم الطبيب</th> 
         <th>النوع</th> 
        </tr> 
        </thead> 
        <div ng-controller="myController"> 
        <tbody> 
        @foreach ($bookings as $booking) 
          <tr ng-repeat="booking in bookings|filter:searching"> 
          <td align="center"> 
           <a href="{{route('booking.edit',$booking->id)}}" class="btn btn-default"><em class="fa fa-pencil"></em></a> 
           <a class="btn btn-danger"><em class="fa fa-trash"></em></a> 
          </td> 
          <td class="hidden-xs">{{$booking->id }}</td> 


       <th>{{$booking->booking_date }}</th> 
       <th>{{$booking->patient->patient_name }}</th> 
       <td>{{$booking->value }}</td> 
       <td>{{$booking->doctor_name }}</td> 
       <td>{{$booking->tybe }}</td> 
          </tr> 
       @endforeach   
         </tbody> 
       </table> 

       </div> 
       <!-- 
       <div class="panel-footer"> 
       <div class="row"> 
        <div class="col col-xs-4">Page 1 of 5 
        </div> 
        <div class="col col-xs-8"> 
        <ul class="pagination hidden-xs pull-right"> 
         <li><a href="#">1</a></li> 
         <li><a href="#">2</a></li> 
         <li><a href="#">3</a></li> 
         <li><a href="#">4</a></li> 
         <li><a href="#">5</a></li> 
        </ul> 
        <ul class="pagination visible-xs pull-right"> 
         <li><a href="#">«</a></li> 
         <li><a href="#">»</a></li> 
        </ul> 
        </div> 
       </div> 
       </div> 
      --> 
      </div> 
      </table> 
<div class="text-center"> 
      {!! $bookings->links(); !!} 
     </div> 
</div></div></div> 

Answer 1

Eager Loading

$bookings = Booking::with(['patient' => function($query) use ($search){ 
    $query->where('patient_name', 'like', '%' . $search . '%'); 
}])->where('status','=', null)->paginate(10); 

，或者如果您不能確定把病人分配給所有人所以你應該使用這樣的查詢：

$bookings = Booking::whereHas('patient', function ($query) use ($search) { 
    $query->where('patient_name', 'like', '%' . $search . '%'); 
})->where('status','=', null)->paginate(10); 

Answer 2

嘗試：

dd($search);

如果你從一些輸入搜索嘗試使用：

$serach = $request->serach;