Laravel無法使用mysql_fetch_array（）

Question

嘗試在Laravel中使用mysql_fetch_array（）時出現錯誤。

while ($row = mysql_fetch_array($query)) 

什麼使用，而不是mysql_fetch_array（）？

錯誤我，

mysql_fetch_array（）預計參數1是資源，數組給定

完整部分，

//prepare the tag cloud array for display 
    $terms = array(); // create empty array 
    $maximum = 0; // $maximum is the highest counter for a search term 

    $query = DB::select('SELECT term, counter FROM search ORDER BY counter DESC LIMIT 30'); 

    while ($row = mysql_fetch_array($query)) 
    { 
     $term = $row['term']; 
     $counter = $row['counter']; 

     // update $maximum if this term is more popular than the previous terms 
     if ($counter > $maximum) $maximum = $counter; 

     $terms[] = array('term' => $term, 'counter' => $counter); 

    } 

Answer 1

DB語句和選擇返回結果，不是一個查詢對象，所以你只需要遍歷結果。

$results = DB::select('SELECT term, counter FROM search ORDER BY counter DESC LIMIT 30'); 

foreach($results as $row) 
{ 
    $term = $row->term; 
    $counter = $row->counter; 

    // update $maximum if this term is more popular than the previous terms 
    if ($counter > $maximum) $maximum = $counter; 

    $terms[] = array('term' => $term, 'counter' => $counter); 

} 

有關通過數據庫類運行原始查詢的詳細信息，請參閱here。