該符號的直角三角形，邊數等於該數字

Question

我正在處理的程序輸出該符號的直角三角形，其邊數等於該數字。它應該做的是終止，如果你輸入0，否則它應該再次要求一個新的輸入。

所以我的問題是如何讓它終止，如果你輸入0，否則要求另一個輸入？我知道我可能需要使用while循環。但是，我該如何改變它？

這裏是我的代碼：

#include <assert.h> 
#include <stdio.h> 
#include <stdlib.h> 

int main() 
{ 
    char s;   /*s is symbol (the input)*/ 
    int a, b, n; /*n is number of rows (the input)*/ 

    printf("Please type the symbol of the triangle:...\n"); /*Ask for symbol input*/ 
    scanf_s("%c", &s, 1); 
    printf("Please type a positive non-zero number between 5 and 35:...\n"); /*Ask for number of rows input*/ 
    scanf_s("%d", &n); 
    assert(n >= 5 && n <= 35); 

    for (a = 1; a <= n; a++) /*How many rows to display+create*/ 
    { 
     for (b = 1; b <= a; b++) 
     { 
      printf("%c", s); 
     } 
     printf("\n"); 
    } 
    system("PAUSE"); 
} 

Answer 1

您可以使用循環來做到這一點。

#include <stdio.h> 
#include <stdlib.h> 

#ifndef _MSC_VER 
/* passing extra arguments to scanf is not harmful */ 
#define scanf_s scanf 
#endif 

int main(void) 
{ 
    char s;   /*s is symbol (the input)*/ 
    int a, b, n; /*n is number of rows (the input)*/ 

    do { 
     printf("Please type the symbol of the triangle:...\n"); /*Ask for symbol  input*/ 
     scanf_s("%c", &s, 1); 
     printf("Please type a positive non-zero number between 5 and 35:...\n");  /*Ask for number of rows input*/ 
     scanf_s("%d", &n); 
     if(n >= 5 && n <= 35) 
     { 
      for (a = 1; a <= n; a++)/*How many rows to display+create*/ 
      { 
       for (b = 1; b <= a; b++) 
       { 
        printf("%c", s); 
       } 
       printf("\n"); 
      } 
     } 
     while ((a = getchar()) != '\n' && a != EOF); /* remove the newline character from standard input buffer */ 
    } while (n != 0); 
    system("PAUSE"); 
}