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我正在編碼數字拼圖遊戲。我有9個按鈕,全部都包含在一個框架中。我的想法是:當按下一個按鈕時,它會檢查它周圍的所有按鈕。如果有一個不可見的按鈕,那個不可見的按鈕將變爲可見,並且按下的按鈕中的數字將變爲可見,並且按下的按鈕將變爲不可見。這就是我所擁有的:數字拼圖編碼
private void Btn1ActionPerformed(java.awt.event.ActionEvent evt) {
if (!Btn2.isVisible()) {
Btn2.setText(Btn1.getText());
Btn2.setVisible(true);
Btn1.setVisible(false);
} else if (!Btn4.isVisible()) {
Btn4.setVisible(true);
Btn4.setVisible(false);
Btn1.setVisible(false);
}
}
private void Btn2ActionPerformed(java.awt.event.ActionEvent evt) {
if (!Btn3.isVisible()) {
Btn3.setText(Btn2.getText());
Btn2.setVisible(false);
Btn3.setVisible(true);
} else if (!Btn1.isVisible()) {
Btn1.setText(Btn2.getText());
Btn1.setVisible(true);
Btn2.setVisible(false);
} else if (!Btn5.isVisible()) {
Btn5.setText(Btn2.getText());
Btn5.setVisible(true);
Btn2.setVisible(false);
}
}
private void Btn3ActionPerformed(java.awt.event.ActionEvent evt) {
if (!Btn2.isVisible()) {
Btn2.setText(Btn3.getText());
Btn3.setVisible(false);
Btn2.setVisible(true);
} else if (!Btn6.isVisible()) {
Btn6.setText(Btn3.getText());
Btn3.setVisible(false);
Btn6.setVisible(true);
}
}
private void Btn4ActionPerformed(java.awt.event.ActionEvent evt) {
// TODO add your handling code here:
if (!Btn1.isVisible()) {
Btn1.setText(Btn4.getText());
Btn1.setVisible(true);
Btn4.setVisible(false);
} else if (!Btn5.isVisible()) {
Btn5.setText(Btn4.getText());
Btn5.setVisible(true);
Btn4.setVisible(false);
} else if (!Btn7.isVisible()) {
Btn7.setText(Btn4.getText());
Btn7.setVisible(true);
Btn4.setVisible(false);
}
}
private void Btn5ActionPerformed(java.awt.event.ActionEvent evt) {
// TODO add your handling code here:
if (!Btn2.isVisible()) {
Btn2.setText(Btn5.getText());
Btn2.setVisible(true);
Btn5.setVisible(false);
}else if (!Btn4.isVisible()) {
Btn4.setText(Btn5.getText());
Btn4.setVisible(true);
Btn5.setVisible(false);
}else if (!Btn6.isVisible()) {
Btn6.setText(Btn5.getText());
Btn6.setVisible(true);
Btn5.setVisible(false);
}else if (!Btn8.isVisible()) {
Btn8.setText(Btn5.getText());
Btn8.setVisible(true);
Btn5.setVisible(false);
}
}
private void Btn6ActionPerformed(java.awt.event.ActionEvent evt) {
// TODO add your handling code here:
if (!Btn3.isVisible()) {
Btn3.setText(Btn6.getText());
Btn3.setVisible(true);
Btn6.setVisible(false);
}else if (!Btn5.isVisible()) {
Btn5.setText(Btn6.getText());
Btn5.setVisible(true);
Btn6.setVisible(false);
}else if (!Btn9.isVisible()) {
Btn9.setText(Btn6.getText());
Btn9.setVisible(true);
Btn6.setVisible(false);
}
}
private void Btn7ActionPerformed(java.awt.event.ActionEvent evt) {
// TODO add your handling code here:
if (!Btn4.isVisible()) {
Btn4.setText(Btn7.getText());
Btn4.setVisible(true);
Btn7.setVisible(false);
}else if (!Btn8.isVisible()) {
Btn8.setText(Btn7.getText());
Btn8.setVisible(true);
Btn8.setVisible(false);
}
}
private void Btn8ActionPerformed(java.awt.event.ActionEvent evt) {
// TODO add your handling code here:
if (!Btn7.isVisible()) {
Btn7.setText(Btn8.getText());
Btn7.setVisible(true);
Btn8.setVisible(false);
}else if (!Btn5.isVisible()) {
Btn5.setText(Btn8.getText());
Btn5.setVisible(true);
Btn8.setVisible(false);
}else if (!Btn9.isVisible()) {
Btn9.setText(Btn8.getText());
Btn9.setVisible(true);
Btn8.setVisible(false);
}
}
private void Btn9ActionPerformed(java.awt.event.ActionEvent evt) {
// TODO add your handling code here:
if (!Btn6.isVisible()) {
Btn6.setText(Btn9.getText());
Btn6.setVisible(true);
Btn9.setVisible(false);
}else if (!Btn8.isVisible()) {
Btn8.setText(Btn9.getText());
Btn8.setVisible(true);
Btn9.setVisible(false);
}
}
它看起來很長很低效。我怎樣才能縮短它?
此代碼是否按預期方式工作? –
一般來說,編號變量總是不好的。使用數組或列表,而不是 –
你將保持各種按鈕的收集和計算鄰接(通過圖型集合或一些基本指標的數學是否) – Rogue