Django：表單處理錯誤。處理與另一個模型關聯的表格

Question

我希望能夠爲教師提交評論。我有2種型號：

models.py

class Teacher(models.Model): 
    user = models.OneToOneField(User, on_delete=models.PROTECT, related_name='Teacher') 

class Review(models.Model): 
    teacher = models.ForeignKey(Teacher) 
    #other fields 

    def __str__(self): 
     return self.name 

forms.py

class ReviewForm(forms.ModelForm): 
    class Meta: 
     model = Review 
     #Note no 'teacher' in fields below 
     fields = ('title','star','body') 

views.py我有以下形式處理：

def teacher_view(request,**kwargs): 
    teacher = Teacher.objects.get(pk=kwargs['pk']) 
    #if request.method == 'POST': 
    #handle the form 
    review_form = ReviewForm(request.POST, instance=teacher) 
    review_form.teacher=teacher 
    if review_form.is_valid(): 
     review_form.save() 
     return redirect('users:index') 
    else: 

出於某種原因，我似乎也得到了其他循環。例如。該表格無效。

Urls.py

url(r'^(?P<pk>[0-9]+)/$', views.teacher_view, name='detail') 

---

全部Views.py

def teacher_profile(request, **kwargs): 
    teacher = Teacher.objects.get(pk=kwargs['pk']) 
    reviews = Review.objects.filter(teacher_id=kwargs['pk']) 
    star = Review.objects.filter(teacher_id=kwargs['pk']).aggregate(Avg('star')) 
    no_of_ratings = Review.objects.filter(teacher_id=kwargs['pk']).count() 

    if request.method == "POST": 
     if 'booking' in request.POST: 
      form = BookingForm(request.POST) 
      if form.is_valid(): 
       #handle the form 
       return redirect('users:index') 
      else: 
       review_form = ReviewForm() 
     elif 'review' in request.POST: 
      review_form = ReviewForm(request.POST) 
      review_form['teacher']=teacher 
      if review_form.is_valid(): 
       review_form.save() 
       return redirect('users:index') 
      else: 
       form = BookingForm() 
     else: 
      form = BookingForm() 
      review_form = ReviewForm() 
    else: 
     form = BookingForm() 
     review_form = ReviewForm() 

    return render(request, "users/teacher_detail.html", context={"form": form, 
                   "review_form":review_form, 
                   "teacher":teacher, 
                   "reviews":reviews, 
                   "star":star, 
                   "no_of_ratings":no_of_ratings, 
                   }) 

我又加了碼。我複製粘貼它從我的views.py，但刪除表單處理，我只是定義變量和重定向到另一個頁面與成功消息。

我想爲什麼你的答案中的邏輯是錯誤的，因爲它首先檢查表單是否有效，這是因爲教師丟失而無效。然後我們在檢查它是否有效之後定義教師。我試圖通過form.is_valid()前加入review_form['teacher']=teacher操縱的代碼，但總是出現錯誤：

'ReviewForm' object does not support item assignment

Answer 1

看起來你要添加的老師，如果ReviewForm是有效的：

def teacher_profile(request,**kwargs): 
    teacher = Teacher.objects.get(pk=kwargs['pk']) 
    reviews = teacher.review_set.all() 
    star = reviews.aggregate(Avg('star')) 
    no_of_ratings = reviews.count() 

    form = BookingForm() 
    review_form = ReviewForm() 

    if request.method == "POST": 
     if 'booking' in request.POST: 
      form = BookingForm(request.POST) 
      if form.is_valid(): 
       #Correct handling 
       return redirect('users:index') 
     elif 'review' in request.POST: 
      review_form = ReviewForm(request.POST) 
      if review_form.is_valid(): 
       review = review_form.save(commit=False) 
       review.teacher = teacher 
       review.save() 
       return redirect('users:index') 
    context = { 
     "form":form, 
     "review_form":review_form, 
     "teacher":teacher, 
     "reviews":reviews, 
     "star":star, 
     "no_of_ratings":no_of_ratings,}) 
    return render(request, "users/teacher_detail.html", context) 

在teacher_detail.html添加，

{{ review_form.errors }}