發言中,我想創建Teradata的遞歸視圖(即CREATE RECURSIVE VIEW
)從以下重複的例子:創建具有遞歸視圖中的「遞歸」中的Teradata
CREATE VOLATILE TABLE vt1
(
foo VARCHAR(10)
, counter INTEGER
, bar INTEGER
)
ON COMMIT PRESERVE ROWS;
INSERT INTO vt1 VALUES ('a', 1, '1');
INSERT INTO vt1 VALUES ('a', 2, '2');
INSERT INTO vt1 VALUES ('a', 3, '2');
INSERT INTO vt1 VALUES ('a', 4, '4');
INSERT INTO vt1 VALUES ('a', 5, '1');
INSERT INTO vt1 VALUES ('b', 1, '3');
INSERT INTO vt1 VALUES ('b', 2, '1');
INSERT INTO vt1 VALUES ('b', 3, '1');
INSERT INTO vt1 VALUES ('b', 4, '2');
WITH RECURSIVE cte (foo, counter, bar, rsum) AS
(
SELECT
foo
, counter
, bar
, bar AS rsum
FROM
vt1
QUALIFY ROW_NUMBER() OVER (PARTITION BY foo ORDER BY counter) = 1
UNION ALL
SELECT
t.foo
, t.counter
, t.bar
, CASE WHEN cte.rsum < 3 THEN t.bar + cte.rsum ELSE t.bar END
FROM
vt1 t JOIN cte ON t.foo = cte.foo AND t.counter = cte.counter + 1
)
SELECT
cte.*
, CASE WHEN rsum < 5 THEN 0 ELSE 1 END AS tester
FROM
cte
ORDER BY
foo
, counter
;
這就產生這樣的輸出:
╔═════╦═════════╦═════╦══════╦════════╗
║ foo ║ counter ║ bar ║ rsum ║ tester ║
╠═════╬═════════╬═════╬══════╬════════╣
║ a ║ 1 ║ 1 ║ 1 ║ 0 ║
║ a ║ 2 ║ 2 ║ 3 ║ 0 ║
║ a ║ 3 ║ 2 ║ 5 ║ 1 ║
║ a ║ 4 ║ 4 ║ 4 ║ 0 ║
║ a ║ 5 ║ 1 ║ 5 ║ 1 ║
║ b ║ 1 ║ 3 ║ 3 ║ 0 ║
║ b ║ 2 ║ 1 ║ 4 ║ 0 ║
║ b ║ 3 ║ 1 ║ 5 ║ 1 ║
║ b ║ 4 ║ 2 ║ 2 ║ 0 ║
╚═════╩═════════╩═════╩══════╩════════╝
我最終想要「保存」爲視圖。我試過CREATE RECURSIVE VIEW
和幾個變種,但我認爲我不瞭解如何避開WITH RECURSIVE cte
聲明。
對於相關的問題,以瞭解發生了什麼事情,看到this question
語法是'create recursive view ....'。以下是該文檔的鏈接:http://www.info.teradata.com/HTMLPubs/DB_TTU_13_10/index.html#page/SQL_Reference/B035_1144_109A/Create_Procedure-Syntax.06.77.html#ww10851072 – Andrew