按匹配的OR條件數對SQL Server記錄進行排序

Question

假設我有一個（代碼生成的）查詢在多個不同的字段中查找關鍵字。例如，術語University,South或Africa中的任何一個可能位於名稱字段或地址字段或其他字段中。我想找到其中任何一個字段匹配任何這些關鍵字的所有記錄：

SELECT * 
FROM 
    Institutions 
WHERE 
    Institutions.name LIKE '%University%' OR 
    Institutions.address LIKE '%University%' OR 
    Institutions.name LIKE '%South%' OR 
    Institutions.address LIKE '%South%' OR 
    Institutions.name LIKE '%Africa%' OR 
    Institutions.address LIKE '%Africa%' 

然而，這是要拉一切。我想根據符合最可能條件的記錄進行排序。

我認爲這會工作，但看起來很笨重：

SELECT * 
FROM 
    Institutions 
WHERE 
    Institutions.name LIKE '%University%' OR 
    Institutions.address LIKE '%University%' OR 
    Institutions.name LIKE '%South%' OR 
    Institutions.address LIKE '%South%' OR 
    Institutions.name LIKE '%Africa%' OR 
    Institutions.address LIKE '%Africa%' 
ORDER BY 
    (
     CASE WHEN Institutions.name LIKE '%University%' THEN 1 ELSE 0 END + 
     CASE WHEN Institutions.address LIKE '%University%' THEN 1 ELSE 0 END + 
     CASE WHEN Institutions.name LIKE '%South%' THEN 1 ELSE 0 END + 
     CASE WHEN Institutions.address LIKE '%South%' THEN 1 ELSE 0 END + 
     CASE WHEN Institutions.name LIKE '%Africa%' THEN 1 ELSE 0 END + 
     CASE WHEN Institutions.address LIKE '%Africa%' THEN 1 ELSE 0 END 
    ) DESC 

有什麼清潔劑？我很喜歡SQL Server特有的解決方案，但純粹的SQL解決方案會很棒。

Answer 1

你可以使用在SQLSERVER全文搜索排名，但我認爲這是一個有點矯枉過正...

反正幾個指針：

http://technet.microsoft.com/en-us/library/ms142524%28v=sql.105%29.aspx

http://technet.microsoft.com/en-us/library/cc879245.aspx

或者，如果您從案例創建函數 - 當返回計數的事物時，您可以在where中使用相同的函數。 （這也是哈克......）

Answer 2

您的解決方案看起來不錯給我，但這裏的別的東西，應該工作（僞代碼）：

​​

Answer 3

也許是這樣的：

SELECT * FROM (
    SELECT i.*, 
    (
     CASE WHEN i.name LIKE '%University%' THEN 1 ELSE 0 END + 
     CASE WHEN i.address LIKE '%University%' THEN 1 ELSE 0 END + 
     CASE WHEN i.name LIKE '%South%' THEN 1 ELSE 0 END + 
     CASE WHEN i.address LIKE '%South%' THEN 1 ELSE 0 END + 
     CASE WHEN i.name LIKE '%Africa%' THEN 1 ELSE 0 END + 
     CASE WHEN i.address LIKE '%Africa%' THEN 1 ELSE 0 END 
    ) AS rnk 
    FROM Institutions i 
) result 
WHERE result.rnk > 0 
ORDER BY result.rnk DESC 

編輯：我忘了上Apply

SELECT * 
FROM 
    Institutions i 
CROSS APPLY 
(
     SELECT 
    (CASE WHEN i.name LIKE '%University%' THEN 1 ELSE 0 END + 
     CASE WHEN i.address LIKE '%University%' THEN 1 ELSE 0 END + 
     CASE WHEN i.name LIKE '%South%' THEN 1 ELSE 0 END + 
     CASE WHEN i.address LIKE '%South%' THEN 1 ELSE 0 END + 
     CASE WHEN i.name LIKE '%Africa%' THEN 1 ELSE 0 END + 
     CASE WHEN i.address LIKE '%Africa%' THEN 1 ELSE 0 END) as rnk 
) c 
ORDER BY c.rnk DESC 

Small example