PHP - 爆炸字符串，並插入到多行與foreach太慢

Question

我想用一個空格爆炸一個字符串，檢查該字是否已經存在。如果沒有，在mysql db中插入每行到多行。我已經試過這之前...

<?php 
if($_SERVER['REQUEST_METHOD'] == 'POST') { 
    include("connect.php"); 
    $counter = 0; 
    $counters = 0; 
    $string = mysql_real_escape_string($_POST['words']); 
    $arr = explode(" ",$string); 
    foreach($arr as $str) { 
     $sql = mysql_query("SELECT * FROM unicode WHERE word = '$str'") or die (mysql_error()); 
     if (mysql_num_rows($sql) == 0) { 
      $sqli = mysql_query("INSERT INTO unicode (word) VALUES ('$str')") or die (mysql_error()); 
      $counters++; 
     } elseif (mysql_num_rows($sql) > 0) { 
      $counter++; 
     } 
    } 
    header("Location: ../addspellwords?success=457394056369&entered=$counters&duplicates=$counter"); 
} 
?> 

這是太過太緩慢....

是否有任何其他方式做到這一點？

謝謝。

Answer 1

根據通過的內容，您可以去SELECT當前存在的字詞，然後將這些字詞留在INSERT之外。如果您的word列是一個關鍵字（我希望根據您的代碼），另一個選項可能是INSERT...ON DUPLICATE KEY。請嘗試以下操作：

<?php 
if($_SERVER['REQUEST_METHOD'] == 'POST') { 
    include("connect.php"); 
    $counter = 0; 
    $counters = 0; 
    $string = mysql_real_escape_string($_POST['words']); 
    $arr = explode(" ",$string); 

    $sql = mysql_query("SELECT `word` FROM unicode WHERE word IN ('".implode("', '", $arr) . ")") or die (mysql_error()); 
    $dupes = array(); 
    while($r = mysql_fetch_assoc($sql) { 
     $dupes[] = $r['word']; 
    } 
    $newwords = array_diff($arr, $dupes); 
    if(count($newwords)) { 
     $sqli = mysql_query("INSERT INTO unicode (word) VALUES ('" . implode("'),('", $newwords) . "')") or die (mysql_error()); 
    } 
    header("Location: ../addspellwords?success=457394056369&entered=".count($newwords)."&duplicates=".count($dupes)); 
} 
?>