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我使用jQuery對話框來加載視圖，該視圖用於將文件上傳到我的應用程序。在瀏覽文件並點擊提交後，調用一個控制器，該控制器處理該文件並將其傳遞給我的模型進行插入。該模型然後返回到控制器，成功（或不），並加載成功（或不成功）的新視圖。從Controller/View加載jQuery對話框？
我想成功（或不）在相同的jQuery對話框（或打開一個新的）而不是調用/加載整個視圖。
我會從我的控制器中調用/加載（不知何故）jQuery對話框？或者我會讓我的控制器調用新的視圖，一旦它加載，讓它呈現對話框，基本上在對話框中呈現自己？希望這是有道理的。
謝謝。
**編輯：添加代碼如下+評論 - 謝謝！ **
我INTIAL視圖包含以下jQuery函數，這是當一個用戶點擊一個錨稱爲（「上傳文件」）：
$(document).ready(function(){
function uploadImage(event) {
id = $(this).data('id'); //id is an URL such as ('upload_form'/do_upload/5) it calls my controller (uploadimage), and passes a value (5) to a function (doupload)
$("#dialog").load(id).dialog(); //loads the URL
return false;
}
$('.imageBtn').live('click',uploadImage);
});
由控制器調用的函數：
function do_upload()
{
$config['upload_path'] = './uploads/';
$config['allowed_types'] = 'gif|jpg|png';
$config['max_size'] = '0';
$config['max_width'] = '212';
$config['max_height'] = '118';
$this->load->library('upload', $config);
if (! $this->upload->do_upload())
{
$data['id'] = $this->input->post('iEventID', true);
$data['error'] = $this->upload->display_errors();
$this->load->view('admin/upload_form', $data); // If an error is found during file/img upload, then the code reloads the view that was previously loaded into my dialogue. This is where I need the same view to reload in the dialog and present the error message. This currently loads the view in its entirety in a browser window.
}
else
{
$upload_data = $this->upload->data();
$filename = $upload_data['file_name'];
$this->event_model->addEventImage($filename);
$this->load->view('admin/upload_success'); // If all is well, instead of loading the view in its entirety, I want to load the success into the dialog previously popped.
}
}
我們可以看到一些代碼嗎？你做了一個體面的工作來解釋這個問題，但如果我們看到你現在的代碼，那麼給你指點會更清楚和更容易。 – slandau
添加上面的代碼。謝謝！ – user464180